Mystic Posted November 17, 2005 Share Posted November 17, 2005 1. TWo different integers are to be selected from a set of 10 different integers in which half of the integers are even and half are odd. how many of the 45 possible selections consists of one even and one odd integer ? Ans->25 2. 7 one dollar bills are to be distributed among Lucia Gomez and Domingo so that each person receives at least one dollar. column A -> The number of ways to distribute the bills so that at least one person receives at least $3 Column B-> The total number of ways to distribute the bills Ans -> The two quantities are equal Quote Link to comment Share on other sites More sharing options...
vaggs Posted November 17, 2005 Share Posted November 17, 2005 for the first question: since there r 5 even and 5 odd no.s therefore selecting one even and one odd will give us:- 5C1 * 5C1 = 25 Quote Link to comment Share on other sites More sharing options...
rehoot Posted November 17, 2005 Share Posted November 17, 2005 1) the first problem is probably easier than you were thinking it was. If you have 10 integers and half are even and half are odd, then you really have two sets of 5. If you want to draw one even and one odd, you are drawing one from the set of 5 odds and one from the set of 5 evens. the combinations are 5 in the first drawing and 5 in the second drawing, making 5*5 total combinations = 25. 2) I was wondering if there was a typo, but I figured that "Lucia Gomez" is one person and "Domingo" is a second person, so if you have $7 and you distribute it all the only combinations are $3 for L and $4 for D or vice versa (two combinations). If you read the criteria under A and B, this method is both the only way to distribute all of the money and the only way to distribute it so that each person gets at least $3, so A and B are each 2, and the answer is C. Quote Link to comment Share on other sites More sharing options...
kronique Posted November 17, 2005 Share Posted November 17, 2005 2) I was wondering if there was a typo, but I figured that "Lucia Gomez" is one person and "Domingo" is a second person, so if you have $7 and you distribute it all the only combinations are $3 for L and $4 for D or vice versa (two combinations). If you read the criteria under A and B, this method is both the only way to distribute all of the money and the only way to distribute it so that each person gets at least $3, so A and B are each 2, and the answer is C. so how wud it be for 3 ppl..:hmm: ...wont work i guess.... Quote Link to comment Share on other sites More sharing options...
manwiththemission2005 Posted November 18, 2005 Share Posted November 18, 2005 If you have 7 similar things that need to be divided among 3 people such that each person recieves atleast 1, then the most equal way to do this is to have a 3-2-2 split. i.e. someone is always left with atleast 3 things. So, A and B mean the same thing. Quote Link to comment Share on other sites More sharing options...
jose Posted November 18, 2005 Share Posted November 18, 2005 2) I was wondering if there was a typo, but I figured that "Lucia Gomez" is one person and "Domingo" is a second person, so if you have $7 and you distribute it all the only combinations are $3 for L and $4 for D or vice versa (two combinations). If you read the criteria under A and B, this method is both the only way to distribute all of the money and the only way to distribute it so that each person gets at least $3, so A and B are each 2, and the answer is C. yes, Lucia Gomez is one person (Lucia is the name and Gomez the last name). No doubt at all Quote Link to comment Share on other sites More sharing options...
Mystic Posted November 18, 2005 Author Share Posted November 18, 2005 Thanks guys Here is another one Please solve this y=x+1/x Column A: value of Y Column B: 100 Ans->D: The relationship cannot be determined with the info given Quote Link to comment Share on other sites More sharing options...
manwiththemission2005 Posted November 18, 2005 Share Posted November 18, 2005 Put x= 1/100, y>100 Put x=1, y Ans is D Quote Link to comment Share on other sites More sharing options...
rp2005 Posted November 18, 2005 Share Posted November 18, 2005 y can't one assume x=0..in this case answer wd b indeterminate Quote Link to comment Share on other sites More sharing options...
rp2005 Posted November 18, 2005 Share Posted November 18, 2005 y can't one assume x=0 ?answer wd b indeterminate.. Quote Link to comment Share on other sites More sharing options...
manwiththemission2005 Posted November 18, 2005 Share Posted November 18, 2005 Well 0 Quote Link to comment Share on other sites More sharing options...
Mystic Posted November 18, 2005 Author Share Posted November 18, 2005 Thanks manwiththemission2005 Sorry that I forgot to type that in Anyway My GRE is on 20th so wish me Good Luck Buy & Thanks Quote Link to comment Share on other sites More sharing options...
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