mishu007 Posted September 3, 2006 Share Posted September 3, 2006 Plz check out the picture and help me.............. Quote Link to comment Share on other sites More sharing options...
Fledgling Posted September 3, 2006 Share Posted September 3, 2006 For column B---- seven bills can be distributed in 7C3 ways = 35 For column A -------- At leastone should get $3 means--- three cases--- one get $3 or $4 or $5 ways---- 3C1*4C2 + 4C1*3C2 + 5C1*2C2 ===> 35 case 1: one getting $3. Now remaining four dollars can be distributed to two persons similarly for other cases also. Answer is C. Quote Link to comment Share on other sites More sharing options...
mishu007 Posted September 3, 2006 Author Share Posted September 3, 2006 But i have a problem... for column B seven bills can be distributed in 7C3 ways = 35 there is an another option, that each one should receive $1. but in those 35 cases you haven't consider that.. i think the no. of cases will be less if u consider the 2nd option. Quote Link to comment Share on other sites More sharing options...
Fledgling Posted September 3, 2006 Share Posted September 3, 2006 Mishu007 The questios says "each person should recieve atleast $1" and column B is asking about the total number of ways of doing this, that will be 7C3. If u give only $1 to each what will happen of remaining money. Hope this helps. Regards Quote Link to comment Share on other sites More sharing options...
veroniquaz Posted September 3, 2006 Share Posted September 3, 2006 fledging: your answer is correct but the way of calculating is completely wrong. with 7C3 you are not answering the question of in how many ways you can distribute the money but rather how many different groups containing 3 bills you can create from 7 bills. This does not make much sense as you do not care which bill exactly the people are holding but rather you are interested in their total value. For me the easiest way of solving this problem is to think of how you can redistribute the remaining 4 dollars among the 3 people. First I would give one more dollar to each person. Afterwards I will be left with one remaining dollar. To whoever I decide to give it, there always will be one person having at least 3. You do not even have to think further because if you already in the beginning decided to give 2, 3 or all 4 remaining dollars to just one person you would always have somebody having at least 3 bills. The answer here obviously is C. Quote Link to comment Share on other sites More sharing options...
mishu007 Posted September 4, 2006 Author Share Posted September 4, 2006 fledging: your answer is correct but the way of calculating is completely wrong. with 7C3 you are not answering the question of in how many ways you can distribute the money but rather how many different groups containing 3 bills you can create from 7 bills. This does not make much sense as you do not care which bill exactly the people are holding but rather you are interested in their total value. For me the easiest way of solving this problem is to think of how you can redistribute the remaining 4 dollars among the 3 people. First I would give one more dollar to each person. Afterwards I will be left with one remaining dollar. To whoever I decide to give it, there always will be one person having at least 3. You do not even have to think further because if you already in the beginning decided to give 2, 3 or all 4 remaining dollars to just one person you would always have somebody having at least 3 bills. The answer here obviously is C. I think this is the right procedure...what about others think? let's see.... Quote Link to comment Share on other sites More sharing options...
dasguptachandan Posted September 4, 2006 Share Posted September 4, 2006 fledging: your answer is correct but the way of calculating is completely wrong. with 7C3 you are not answering the question of in how many ways you can distribute the money but rather how many different groups containing 3 bills you can create from 7 bills. This does not make much sense as you do not care which bill exactly the people are holding but rather you are interested in their total value. For me the easiest way of solving this problem is to think of how you can redistribute the remaining 4 dollars among the 3 people. First I would give one more dollar to each person. Afterwards I will be left with one remaining dollar. To whoever I decide to give it, there always will be one person having at least 3. You do not even have to think further because if you already in the beginning decided to give 2, 3 or all 4 remaining dollars to just one person you would always have somebody having at least 3 bills. The answer here obviously is C. wow!! that was a really smart way to solve this problem !!!! No calculations and Bingo answer [clap] Quote Link to comment Share on other sites More sharing options...
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