Plz, Solve Maths problem

[hena124]

1)In a grp 60% likes classical music .40% don’t like classical music. 18% like both classical and jazz.
colA:: % of people who likes classical music also likes jazz music
colB:: 30%

2)other qu is based on set theory 200 total person 78% are not included in it
10 % is a 15% is b find values which are included in a & b

3)a man is known to speak truth 3 outof 4 times. he thorws a die and reports it as 6. the probability that it is exactly 6 is
a)3/4 b)5/8 c)2/5 d)3/5 e)4/5

4) que is to find out the range of following table.
CLASS | frequency
15-25 | 05
25-35 | 12
35-45 | 45
45-55 | 18

5)given some sides of a triangle as 10,8.1,6.1 and asked to find the angle b/n 8.1 and 6.1 ?
col a col b
x 90

6)Measurement Frequency
10 4
20 x
30 y
40 10
total 24
soln:

Find average arithmatic mean of 24 measurement
options:
20
25
30
35
50

7)xy!=0 (factorial) x/y=y/x x!=y

col col B
x+y 0

[sruthi07]

can you be more lucid when posting ??
thanks!

[dipen01]

Indeed u should right it in better way so that everybody can understand them. anyways...

Well i am not in touch with Range,Frequencies and stuff..

1) I doubt if the answer is 'C'...coz then it would be very straight forward..!!

Originally Posted by nimeshsk
1st question:

consider a group of 100.
So then 60 like classical music.
18 like both classical and jazz.
% of people who likes classical music also likes jazz music will be
(18/60)*100 = 30 %

both coloumn r equal

2)

Well i dint understood the question...but i m tryin to decipher it... i guess the question means...

Out of 200 Total Person, 78% are excluded and there are two sets of 10% as 'a' and 15% as 'b' and we are suppose to find the intersection between a a and b...well even this seems to be very simple...but what can i say...didnt understood the question.....

so it can be....78 + 10 + 15 - x = 100

so x = 3 and interesection is 3%

and so 3% of 200 is 6.... so answer that i feel is 6... I guess im wrong but what the heck...

3) 3/4

4) No Idea

5) 'B'

X<90 degrees...

(8.1^2) + (6.1^2) > (10.1^2)... so angle will be less than 90..

6) I feel the question is incompelte as no relation is given between x and y

7) Well just by observin one condition x!=y i.e y cannot be zero or negative..!! so col A has to be bigger..!!

So i would think its 'A'


Can someone posts Official Answer or atleast Readable Questions..!!

[rocky80]

2)other qu is based on set theory 200 total person 78&#37; are not included in it
10 % is a 15% is b find values which are included in a & b

3)a man is known to speak truth 3 outof 4 times. he thorws a die and reports it as 6. the probability that it is exactly 6 is
a)3/4 b)5/8 c)2/5 d)3/5 e)4/5

4) que is to find out the range of following table.
CLASS | frequency
15-25 | 05
25-35 | 12
35-45 | 45
45-55 | 18

5)given some sides of a triangle as 10,8.1,6.1 and asked to find the angle b/n 8.1 and 6.1 ?
col a col b
x 90

6)Measurement Frequency
10 4
20 x
30 y
40 10
total 24
soln:

Find average arithmatic mean of 24 measurement
options:
20
25
30
35
50

7)xy!=0 (factorial) x/y=y/x x!=y

col col B
x+y 0

2.78% not included => 22% included =>44 included

44 = 20 + 30 - y

y = 6 =12%

3. none of the given options is correct, the answer is = 3/8


4. range should be 55-15 = 40

5. x^2 + y^2 > z^2
i think it should be A, well even im not sure....

6. answer should be = 30

7. x! = y =a positive no.

xy! = 0 => x = zero

x/y = y/x

=> (x-y)*(x+y) = 0

x-y is not 0

so x+y = 0

answer = C [if i m not wrong...]

[dipen01]

@rocky :- Would you care to explain your answers..!! Ideally it should be that way i guess....!!

btw

7. x! = y =a positive no.
xy! = 0 => x = zero
x/y = y/x
=> (x-y)*(x+y) = 0
x-y is not 0
so x+y = 0
answer = C [if i m not wrong...]

wen x!=y and x = 0 (as it was proved)...
shouldnt y = 1 (since 0! = 1)

then if we calculated x + y it gives 0 + 1 = 1...
That way i got it 'A'... Just Curious..!!


Regarding

5)given some sides of a triangle as 10,8.1,6.1 and asked to find the angle b/n 8.1 and 6.1 ?
col a col b
x 90

i still think its 'B'

...Can anyone post Official Answer.....

how did u get 3/8 for

3)a man is known to speak truth 3 outof 4 times. he thorws a die and reports it as 6. the probability that it is exactly 6 is
a)3/4 b)5/8 c)2/5 d)3/5 e)4/5

I forgot lotsa main concepts... Damn need to revise everything

[rocky80]

@rocky :- Would you care to explain your answers..!! Ideally it should be that way i guess....!!

btw


wen x!=y and x = 0 (as it was proved)...
shouldnt y = 1 (since 0! = 1)

then if we calculated x + y it gives 0 + 1 = 1...
That way i got it 'A'... Just Curious..!!


Regarding



i still think its 'B'

...Can anyone post Official Answer.....

how did u get 3/8 for



I forgot lotsa main concepts... Damn need to revise everything

seee 7th question is not clear...

either x -y = 0 or x +y = 0

so wt it can be?...question is still not clear and the author is sleeping....
so lets leave that...

regarding 5th question, even im not sure...so leave that too

3. see how cum u say its 3/4?

man reports 6 on two occasions

1. its actually a six
2. its not a six

when its six, p = 1/6 and he reports it six =3/4 so p1= 3/24

secondly, when its not six p =5/6, and he lies = 1/4, so p2= 5/24

now p = p1/(p1+p2) = 3/8

[dipen01]

oh thanx.......

Conditional Probability........

[rezbipul]

6. answer should be = 30

How????