1. Good post? |

hi can any one solve one of my querries please.

there 6 guys and 4 girls..
what is the probability of seating all the guys and gals in such a way that no two girls sit together....

i dont remember the option right now.. but i'm sure all the options were in the range of 14440... and 64440 can anyone help me solve this one....
i got a solution which wasn't in the option

2. Good post? |
I'm assuming the question is no. of ways in which all the guys and gals can sit in such a way that no two girls sit together since the options r in the range 14440... and 64440...so obv the question was not asking abt probability...

Total no. of ways in which 6 guys n 4 girls can sit together = 10!
if 2 gals r always made 2 sit together then they can b treated as one single entity...so total no. of earthlings = 6(guys)+2(gals)+1(2 gals treated as one) = 9 and they can b seated in 9! ways...
Also the 2 girls who r a part of the single entity can sit in 2 ways...so total no. of permutations possible in this case = 9!*2

so, no. of ways in which all the guys and gals can sit in such a way that no two girls sit together = 10! - 9!*2

3. Good post? |
none of the options were similar to the one that u gave me ...

4. Good post? |
none of the options were similar to the one that u gave me ...

5. Good post? |
it shud be 5!* 6P4

6. Good post? |
Originally Posted by rocky80
it shud be 5!* 6P4
even this is not in the option can anyone tell me how to solve this rather than giving solution please...

7. Good post? |
Hi I think the solution is 17280

The reason why I think the solution is because you have 10 places whey they are supossed to sit

in first place we put a boy there are 6 candidates to sit
in the second place we put a girl there are 4 cadidates to sit
in third place we put a boy there are 5 candidates to sit
in fourht place we put a girl there are 3 candidates to sit
in 5th place we put a boy there are 4 candidates to sit
in 6th place we put a girl there are 2 candidates to sit
in 7th place we put a boy there are 3 candidates to sit
in 8th place we put a girl there are 1 candidates to sit
in 9th place we put a boy there are 2 candidates to sit
in 10th place we put a boy there are 1 candidates to sit

so the solution might be 6!*4! because the girls are independent from the boys, I don't really remember probability, I will start preparing this test tomorrow so maybe i can help you in the future

There are currently 1 users browsing this thread. (0 members and 1 guests)

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•

SEO by vBSEO ©2010, Crawlability, Inc.