please help me solve this...

**vackamania** · 02-15-2007, 03:06 AM

hi can any one solve one of my querries please.

there 6 guys and 4 girls..
what is the probability of seating all the guys and gals in such a way that no two girls sit together....

i dont remember the option right now.. but i'm sure all the options were in the range of 14440... and 64440 can anyone help me solve this one....
i got a solution which wasn't in the option

please help me solve this ...

**thegoat** · 02-15-2007, 05:36 AM

I'm assuming the question is no. of ways in which all the guys and gals can sit in such a way that no two girls sit together since the options r in the range 14440... and 64440...so obv the question was not asking abt probability...

Total no. of ways in which 6 guys n 4 girls can sit together = 10!
if 2 gals r always made 2 sit together then they can b treated as one single entity...so total no. of earthlings = 6(guys)+2(gals)+1(2 gals treated as one) = 9 and they can b seated in 9! ways...
Also the 2 girls who r a part of the single entity can sit in 2 ways...so total no. of permutations possible in this case = 9!*2

so, no. of ways in which all the guys and gals can sit in such a way that no two girls sit together = 10! - 9!*2

**vackamania** · 02-15-2007, 06:17 AM

none of the options were similar to the one that u gave me ...

**vackamania** · 02-15-2007, 06:18 AM

none of the options were similar to the one that u gave me ...

**rocky80** · 02-15-2007, 02:22 PM

it shud be 5!* 6P4

**vackamania** · 02-16-2007, 02:47 PM

Originally Posted by rocky80

it shud be 5!* 6P4

even this is not in the option can anyone tell me how to solve this rather than giving solution please...

**herandiz** · 02-20-2007, 09:14 PM

Hi I think the solution is 17280

The reason why I think the solution is because you have 10 places whey they are supossed to sit

in first place we put a boy there are 6 candidates to sit
in the second place we put a girl there are 4 cadidates to sit
in third place we put a boy there are 5 candidates to sit
in fourht place we put a girl there are 3 candidates to sit
in 5th place we put a boy there are 4 candidates to sit
in 6th place we put a girl there are 2 candidates to sit
in 7th place we put a boy there are 3 candidates to sit
in 8th place we put a girl there are 1 candidates to sit
in 9th place we put a boy there are 2 candidates to sit
in 10th place we put a boy there are 1 candidates to sit

so the solution might be 6!*4! because the girls are independent from the boys, I don't really remember probability, I will start preparing this test tomorrow so maybe i can help you in the future