The areas of two similiar trianles are 25 and 16. If the perimeter of the first is 15 find the perimeter of the second. Goodluck
I know it is 12 but where does the sqrt of the perimeters come on
It is an immediate (almost) result from the definition of similar triangles and from the formula for the area of a triangle.
You may also have a little bit more luck getting people to bite by posting this in the GRE forum. These seem more up their alley.
University of Wisconsin - Madison: Took my Masters and ran.
Let S1 and S2 denote areas of triangles 1 and 2 respectively and P1 and P2 their perimeters.
The solution is trivial, since we have the formula:
5/4=15/P2 >> P2=60/5=12
I am quite sure that every 8th-9th grader in my country would solve this problem without thinking too much.
Likely to attend: Virginia
Accepted: UC Riverside, Penn State
Rejected: Cornell, Berkeley, Harvard, Georgetown
Waiting: don't care anymore
This problem has helped me augment my conception in similitude. If two traingles are equal, then in all cases the ratio of two similar linear dimensions would be same.a1/a2=b1/b2=c1/c2=h1/h2=p1/p2=k (constant)Here, a,b,c are arms and h is height and p is perimeter.
Last edited by KBTA; 06-14-2007 at 10:30 AM. Reason: Correction
There are currently 1 users browsing this thread. (0 members and 1 guests)