hi friends i want explanation on this problem

[affablelochan]

A student has received scores of 88, 82, and 84 on 3 quizzes. If the tests count twice as much as the quizzes, what is the lowest score the student can get on the next test to achieve an average score of at least 80?



*(sum of scores)/(# of scores) = mean
*Need 2 x's since tests count twice
*Solve for x (missing test) *Inverse of div. by 5 is mult. by 5


*Inverse of add 254 is sub. 254




The student would have to score a 73 on the next test to have a mean of 80.

[kobe317]

eaiser way:
88,82,84,x,x =5*80
8, 2, 4, x, x =0
2x=-14
x=-7
so 80-x=73

[prithibi]

hw do u knw the number of tests is 2 and the score is equal?plz explain.i m struggling with it

[us_is_near]

I particularly did not understand this stmt:

" If the tests count twice as much as the quizzes, "


If it says twice, why do we have 2 x's ???

[julle286]

(88+82+84+2x) / 5 = 80

x= 73

IMO easiest solution