03-20-2008, 09:58 PM
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#12 (permalink) |
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Within my grasp!
 Join Date: Jun 2007
Posts: 241
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Sure buddy!
I'll post the answers next, so don't look unless you want to see them early... 20. In a flower shop, there are 5 different types of flowers. Two of the flowers are blue, two are red and one is yellow. In how many different combinations of different colors can a 3-flower garland be made? a) 4. b) 20. c) 3. d) 5. e) 6. 21. In a jar there are balls in different colors: blue, red, green and yellow. The probability of drawing a blue ball is 1/8. The probability of drawing a red ball is 1/5. The probability of drawing a green ball is 1/10. If a jar cannot contain more than 50 balls, how many yellow balls are in the Jar? a) 23. b) 20. c) 24. d) 17. e) 25. 22. In a jar there are 3 red balls and 2 blue balls. What is the probability of drawing at least one red ball when drawing two consecutive balls randomly? a) 9/10 b) 16/20 c) 2/5 d) 3/5 e) ½ 23. In Rwanda, the chance for rain on any given day is 50%. What is the probability that it rains on 4 out of 7 consecutive days in Rwanda? a) 4/7 b) 3/7 c) 35/128 d) 4/28 e) 28/135 24. A Four digit safe code does not contain the digits 1 and 4 at all. What is the probability that it has at least one even digit? a) ¼ b) ½ c) ¾ d) 15/16 e) 1/16 25. John wrote a phone number on a note that was later lost. John can remember that the number had 7 digits, the digit 1 appeared in the last three places and 0 did not appear at all. What is the probability that the phone number contains at least two prime digits? a) 15/16 b) 11/16 c) 11/12 d) ½ e) 5/8 26. What is the probability for a family with three children to have a boy and two girls (assuming the probability of having a boy or a girl is equal)? a) 1/8 b) ¼ c) ½ d) 3/8 e) 5/8 27. In how many ways can you sit 8 people on a bench if 3 of them must sit together? a) 720 b) 2,160 c) 2,400 d) 4,320 e) 40,320 28. In how many ways can you sit 7 people on a bench if Suzan won’t sit on the middle seat or on either end? a) 720 b) 1,720 c) 2,880 d) 5,040 e) 10,080 29. In a jar there are 15 white balls, 25 red balls, 10 blue balls and 20 green balls. How many balls must be taken out in order to make sure we took out 8 of the same color? a) 8 b) 23 c) 29 d) 32 e) 53 30. In a jar there are 21 white balls, 24 green balls and 32 blue balls. How many balls must be taken out in order to make sure we have 23 balls of the same color? a) 23 b) 46 c) 57 d) 66 e) 67 31. What is the probability of getting a sum of 12 when rolling 3 dice simultaneously? a) 10/216 b) 12/216 c) 21/216 d) 23/216 e) 25/216 32. How many diagonals does a polygon with 21 sides have, if one of its vertices does not connect to any diagonal? a) 21 b) 170 c) 340 d) 357 e) 420 33. How many diagonals does a polygon with 18 sides have if three of its vertices do not send any diagonal? a) 90 b) 126 c) 210 d) 264 e) 306 34. What is the probability of getting a sum of 8 or 14 when rolling 3 dice simultaneously? a) 1/6 b) ¼ c) ½ d) 21/216 e) 32/216 35. The telephone company wants to add an area code composed of 2 letters to every phone number. In order to do so, the company chose a special sign language containing 124 different signs. If the company used 122 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 124 signs? a) 246 b) 248 c) 492 d) 15,128 e) 30,256 36. How many 8-letter words can be created using computer language (0/1 only)? a) 16 b) 64 c) 128 d) 256 e) 512 37. How many 5 digit numbers can be created if the following terms apply: the leftmost digit is even, the second is odd, the third is a non even prime and the fourth and fifth are two random digits not used before in the number? a) 2520 b) 3150 c) 3360 d) 6000 e) 7500 38. A drawer holds 4 red hats and 4 blue hats. What is the probability of getting exactly three red hats or exactly three blue hats when taking out 4 hats randomly out of the drawer and returning each hat before taking out the next one? a) 1/8 b) ¼ c) ½ d) 3/8 e) 7/12 39. Ruth wants to choose 4 books to take with her on a camping trip. If Ruth has a total of 11 books to choose from, how many different book quartets are possible? a) 28 b) 44 c) 110 d) 210 e) 330 40. A computer game has five difficulty levels. In each level you can choose among four different scenarios except for the first level, where you can choose among three scenarios only. How many different games are possible? (Remember that this does not ask about how many combinations of games can be possible, its simply how many different games are possible). a) 18 b) 19 c) 20 d) 21 e) None of the above 41. How many four-digit numbers that do not contain the digits 3 or 6 are there? a) 2401 b) 3584 c) 4096 d) 5040 e) 7200 42. How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number? a) 1875 b) 2000 c) 2375 d) 2500 e) 3875 43. In a department store prize box, 40% of the notes give the winner a dreamy vacation; the other notes are blank. What is the approximate probability that 3 out of 5 people that draw the notes one after the other, and immediately return their note into the box get a dreamy vacation? a) 0.12 b) 0.23 c) 0.35 d) 0.45 e) 0.65 44. A six sided dice with faces numbered 1 thru 6 is rolled twice. What is the probability that the face with number 2 on it would not be facing upward on either roll? A. 1/6 B. 2/3 C. 25/36 D. 17/18 E. 35/36 |
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03-20-2008, 10:00 PM
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#13 (permalink) |
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Within my grasp!
Join Date: Jun 2007
Posts: 241
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20. The best answer is A.
We want to make a 3-flower garlands, each should have three colors of flowers in it. There are two different types of blue and two different types of red. The options are (2 blue) x (2 red) x (1 yellow) = 4 options. 21. The best answer is A. If 1/8 is the probability of drawing a blue ball then there are 40/8 = 5 blue balls in the jar. And with the same principle there are 8 red balls and 4 green ones. 40 – 5 – 8 – 4 = 23 balls (yellow is the only color left). 22. The best answer is A. Since we want to draw at least one red ball we have four different possibilities: 1. Drawing blue-blue. 2. Drawing blue-red. 3. Drawing red-blue. 4. Drawing red-red. There are two ways to solve this question: One minus the probability of getting no red ball (blue-blue): 1-2/5 x ¼ = 1-2/20 = 18/20 = 9/10/ Or summing up all three good options: Red-blue --> 3/5 x 2/4 = 6/20. Blue-red --> 2/5 x ¾ = 6/20. Red-red --> 3/5 x 2/4 = 6/20. Together = 18/20 = 9/10. 23. The best answer is C. We have 7!/(4!*3!) = 35 different possibilities for 4 days of rain out of 7 consecutive days (choosing 4 out of seven). Every one of these 35 possibilities has the following probability: every day has the chance of ½ to rain so we have 4 days of ½ that it will rain and 3 days of ½ that it will not rain. We have ½ to the power of 7 = 1/128 as the probability of every single event. The total is 35 x 1/128 = 35/128. 24. The best answer is D. For every digit we can choose out of 8 digits (10 total minus 1 and 4). There are four different options: 5. No even digits 6. One even digit. 7. Two even digits. 8. Three even digits. 9. Four even digits. The probability of choosing an odd (or an even) digit is ½. One minus the option of no even digits: 1- (1/2)4= 15/16. You can also sum up all of the other options (2-5). 25. The best answer is B. Since 1 appears exactly three times, we can solve for the other four digits only. For every digit we can choose out of 8 digits only (without 1 and 0). Since we have 4 prime digits (2, 3, 5, 7) and 4 non-prime digits (4, 6, 8, 9), the probability of choosing a prime digit is ½. We need at least two prime digits: One minus (the probability of having no prime digits + having one prime digit): There are 4 options of one prime digit, each with a probability of (1/2)4. There is only one option of no prime digit with a probability of (1/2)4. So: [1- ((1/2)4+(1/2)4*4)] = 11/16. 26. The best answer is D. There are three different arrangements of a boy and two girls (boy, girl, girl), (girl, boy, girl), (girl, girl, boy). Each has a probability of (1/2)3. The total is 3*(1/2)3=3/8. 27. The best answer is D. Treat the three that sit together as one person for the time being. Now, you have only 6 people (5 and the three that act as one) on 6 places: 6!=720. Now, you have to remember that the three that sit together can also change places among themselves: 3! = 6. So, The total number of possibilities is 6!*3!= 4320. 28. The best answer is C. First, check Suzan: she has 4 seats left (7 minus the one in the middle and the two ends), After Suzan sits down, the rest still have 6 places for 6 people or 6! Options to sit. The total is Suzan and the rest: 4*6! = 2880. 29. The best answer is C. The worst case is that we take out seven balls of each color and still do not have 8 of the same color. The next ball we take out will become the eighth ball of some color and our mission is accomplished. Since we have 4 different colors: 4*7(of each) +1=29 balls total. Of course you could take out 8 of the same color immediately, however we need to make sure it happens, and we need to consider the worst-case scenario. 30. The best answer is D. The worst case would be to take out 21 white balls, 22 green and 22 blue balls and still not having 23 of the same color. Take one more ball out and you get 23 of either the green or the blue balls. Notice that you cannot get 23 white balls since there are only 21, however, you must consider them since they might be taken out also. The total is: 21+22+22+1= 66. 31. The best answer is E. Start checking from the smaller or bigger numbers on the dice. We will check from bigger numbers working downwards: start with 6, it has the following options: (6,5,1), (6,4,2), (6,3,3). Now pass on to 5: (5,5,2), (5,4,3). Now 4: (4,4,4). And that’s it, these are all number combinations that are possible, if you go on to 3, you will notice that you need to use 4, 5 or 6, that you have already considered (the same goes for 2 and 1). Now analyze every option: 6,5,1 has 6 options (6,5,1), (6,1,5), (5,1,6), (5,6,1), (1,6,5), (1,5,6). So do (6,4,2) and (5,4,3). Options (6,3,3) and (5,5,2) have 3 options each: (5,5,2), (5,2,5) and (2,5,5). The same goes for (6,3,3). The last option (4,4,4) has only one option. The total is 3*6+2*3+1=18+6+1 = 25 out of 216 (63) options. 32. The best answer is B. We have 20 vertices linking to 17 others each: that is 17*20=340. We divide that by 2 since every diagonal connects two vertices. 340/2=170. The vertex that does not connect to any diagonal is just not counted. 33. The best answer is A. We have 15 Vertices that send diagonals to 12 each (not to itself and not to the two adjacent vertices). 15*12=180. Divide it by 2 since any diagonal links 2 vertices = 90. The three vertices that do not send a diagonal also do not receive any since the same diagonal is sent and received. Thus they are not counted. 34. The best answer is A. The options for a sum of 14: (6,4,4) has 3 options, (6,5,3) has 6 options, (6,6,2) has 3 options, (5,5,4) has 3 options. We have 15 options to get 14. The options for a sum of 8: (6,1,1) has 3 options, (5,2,1) has 6 options, (4,3,1) has 6 options, (4,2,2) has 3 options, (3,3,2) has 3 options. We have 21 options to get 8. Total: 21+15= 36/216 = 1/6. 35. The best answer is C. The phone company already created 122*122 area codes, now it can create 124*124. 1242-1222=(124+122)(124-122) = 246*2 = 492 additional codes. There are other ways to solve this question. However this way is usually the fastest. 36. The best answer is D. Every letter must be chosen from 0 or 1 only. This means we have two options for every word and 28 = 256 words total. 37. The best answer is A. The first digit has 4 options (2,4,6,8 and not 0), the second has 5 options (1,3,5,7,9) the third has 3 options (3,5,7 and not 2), the fourth has 7 options (10-3 used before) and the fifth has 6 options (10-4 used before). The total is 4*5*3*7*6=2520. 38. The best answer is C. Getting three red out of 4 that are taken out has 4 options (4!/(3!*1!)) each option has a probability of (1/2)4 since drawing a red or blue has a 50% chance. 4*1/16= ¼ to get three red hats. The same goes for three blue hats so ¼+¼ =1/2. The probability to get 3 red or 3 blue can be expressed as follows: (Prob to get 3 red + Prob to get 3 blue) Prob to get 3 red = Probability to get 3 red * probability to get 1 blue = Probability to get red * Probability to get red * Probability to get red * Probability to get blue Now, the mistake often created is this probability should take into account the following combinations (R,R,R,B), (R,R,B,R), (R,B,R,R) and (B,R,R,R) (This in short is 4C3) So, the probability to get 3 red = 4 * (1/2) ^ 4 = 1/4 Similarly the probability to get 3 blue hats = 4*(1/2)^4 = 1/4 So, the total probability = ¼ + ¼ = ½ 39. The best answer is E. Choosing 4 out of 11 books is: 11!/(4!*7!) = 330 possibilities. 40. The best answer is . On four levels there are 4 scenarios = 16 different games. The first level has 3 different scenarios. The total is 19 scenarios. 41. The best answer is B. The first digit has 7 possibilities (10 – 0,3 and 6). The other three digits have 8 possibilities each. 7*8*8*8= 3584. 42. The best answer is C. Not considering the fact that 4 cannot appear more than once, we have a total of 4*5*5*5*5=2500. Now we deduct the possibilities where 4 does appear more than once (in this case it can appear only twice on the two leftmost even digits). In order to do so, we put 4 in the first and second leftmost digits. The rest of the digits are odd: 5*5*5=125. 2500-125=2375. 43. The best answer is B. The chance of winning is 0.4 and it stays that way for all people since they return their note. The number of different options to choose 3 winners out of 5 is 5!/(3!*2!) = 10. Each option has a chance of 0.4*0.4*0.4*0.6*0.6 = 0.02304 * 10 = 0.2304. (There is a 0.4 chance to win and 0.6 chance to lose. So, when 3 people win, 2 have to lose. Hence, the calculation is .4*.4*.4*.6*.6 = 0.02304, but this just accounts for the possibility that the first 3 win and the last 2 lose. However, there can be 10 options for choosing this and hence the probability is 0.23 44. The probability that face with no. 2 on it would not face upward on 2 rolls = probability that the first roll does not have 2 facing upward * probability that the second roll does not have 2 facing upward = 5/6*5/6 = 25/36 (The mistake I initially created was I took the probability of occurrence of 2 ‘2s’ as 1/36 and just subtracted it from 1 to get 35/36. But this just takes into account that 2 does not face up on either first or the second roll. We don’t want it in either of the rolls). |
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03-21-2008, 03:09 PM
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#14 (permalink) |
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Eager!
 Join Date: Feb 2008
Posts: 34
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I can't understand the logic of #35.
 Can somebody explain it in an easier way?35. The telephone company wants to add an area code composed of 2 letters to every phone number. In order to do so, the company chose a special sign language containing 124 different signs. If the company used 122 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 124 signs? a) 246 b) 248 c) 492 d) 15,128 e) 30,256 |
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07-12-2008, 11:34 AM
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#16 (permalink) | |
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Within my grasp!
Join Date: Apr 2008
Posts: 168
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Need help here!
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