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Old 05-23-2008, 05:30 PM   #21 (permalink)
auyon
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For the V vs D question, I think this could be an interesting and fast approach:

Consider the numbers in pairs, so consider 1 and 2, then 3 and 4, up to 47 and 48. You will notice that in each pair, the even number is exactly 1 higher than the odd number. So for each pair of numbers, the sum of even numbers will be 1 higher. There are 24 pairs from 1-48, so the sum of even numbers should be 24 higher than the sum of odd numbers.

So

V = D + 24


But column B says D + 23, so it is still lower than V. So the answer is A.
I hope that makes sense
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Old 05-30-2008, 12:23 AM   #22 (permalink)
Oldman
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Quote:
Originally Posted by skawal View Post
kudos gre320hex,
i think, to solve problem like this, one need a keen observation.
It seems like you could just convert these to percents and apply order of operations to solve. Then it becomes an easy arithmetic problem.

Just convert to percents and add/subtract as you go. They test common fraction > percent conversions with this problem. It's good if you can just reason it out, but I would probably take an approach that would give me confidence that my method was full-proof. You should know all of these conversions so just working it out will only take 45 seconds or so. If you forget one, just divide it out and approximate. Reason you can approx. is that they include a lot of fractions like 1/3 that go on forever, so it is unlikely they expect an exact calculation.

100%
- 50%
+33%

etc.

A is bigger.
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Old 06-12-2008, 11:04 AM   #23 (permalink)
ivsham
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It seems that the solutions proposed are for problems, which text is missing. Could someone post them again? Thanks!
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Old 06-16-2008, 11:00 AM   #24 (permalink)
srinathrao.in
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I found the answer to the 'cube-gallon' question as 3g/4(y-w) which is different from choice D.


@rapt0ria
Can I get the test from which you have posted these questions. It would be of great help to me.
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