please help me by solving these problems:part-2

[Jeanette]

Originally Posted by chestnut.cc

There will be 2 nos that end with 0 or 2 in every ten nos... that comes to 40 betn 100 and 299... :s

So the solution to 16 should be 80%, not 81%

[chestnut.cc]

das stimmt

[Jeanette]

Originally Posted by chestnut.cc

10. I'm guessing here since im not sure if I understood the question... if the cuboid is cut vertically into 27 pieces and if the broad side of each piece is considered its face... then there will be only 2 blocks with red faces... namely those chopped off at either end...

No, I don't think that's what it meant. The cube was 3x3x3, and it was cut into 27 pieces. 16 pieces will have red faces and 11 will not.

[chestnut.cc]

A cuboid is mentioned... not a cube... and theres no way of telling its dimensions... if its a cube of dimensions 3*3*3... then 26 pieces will have red faces... Consider the cuboid of dimensions 1*1*27... fits the criterion... but every cube here will have a red face... so the only way to get a consistent ans is if the cuboid is sliced vertically into 27 pieces... their dimensions are irrelevant... and if the broad side is considered a face then the ans is 2... and if any face is considered a face... the ans is 27...

[study_hard]

If (a^3)/(b^3) = -1 then

What is the value of (a^-1)+(b^-1) =

First sentence means that a/b = -1
=> a = -b
so the value of the given expression = 0
No...?