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#1 (permalink) |
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Got it
![]() ![]() Join Date: Jun 2008
Posts: 126
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Slope/intercept tip
This is probably obvious to everyone except me, but if you get a slope/x-y intercept problem, first try to draw the line using the information given. Don't bother trying to solve for x and y. You will quickly be able to see if the slope is positive or negative, steep or shallow, etc. You'll also be able to make a quick estimate of where the intercepts must be.
For example, if the x-intercept equals the y-intercept and x/=/0, just a quick sketch will show you that the slope must be -1. If you're given points, plot the points and take a quick look at which direction the line is pointing. In PP2 I had two slope questions, and the first one I wasted time trying to solve without plotting, until I realized what an easy question it is when you draw in the line. |
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#2 (permalink) |
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Eager!
![]() Join Date: Jun 2008
Posts: 79
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There was a PP2 QC question on slopes which I didn't interpret correctly-
The x intercept is twice the y intercept, choose which is bigger, etc - the slope or 1/2. I misinterpreted this by taking the modulus rather than taking the values with signs ![]() |
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#4 (permalink) |
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Wouldbegood...
![]() ![]() Join Date: Jun 2008
Posts: 260
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yes thats true... simply drawing out the lines often makes things much simpler... however rem that the rules for negatively sloped lines are exactly the opposite... so a flatter line has a greater slope than a steeper line if theyre both downward sloping... using a 45deg line also helps a lot... giving an idea if the slope is greater than or less than 1...
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#5 (permalink) | |
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Trying to make mom and pop proud
Join Date: Jun 2008
Location: Albany, NY
Posts: 12
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Quote:
0= ax+b -b= ax -b/a = x-intercept -b/a=2b (x-intercept is twice the y-intercept) Solve for a: 2ab=-b a=-b/2b a=-1/2 That's just how I did it...seemed easier to me than any kind of graphing. |
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#6 (permalink) |
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Let's get it on
![]() ![]() Join Date: May 2008
Location: India
Posts: 295
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I agree with DattaPlot. I prefer working with equations. Get any equation of a line in the form of y = mx + c, where m is the slope, c is the y-intercept and -c/m is the x-intercept.
I find this faster than figuring out two points on a graph and then drawing the line. |
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#7 (permalink) | |
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Got it
![]() ![]() Join Date: Jun 2008
Posts: 126
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Quote:
I guess we each need to do what works for us.... If you're given the information that x-intercept=y-intercept, playing around with equations is a waste of time if you just plot, say, (3,0) and (0,3). It's quite easy to see which direction the line is pointing. |
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