Go Back   TestMagic Forums > Test preparation > GRE > GRE Math
Register FAQForum Rules Members List Calendar Search Today's Posts Mark Forums Read

Reply
 
LinkBack Thread Tools Display Modes
Old 07-03-2008, 05:51 PM   #1 (permalink)
Jeanette
Got it
 
Join Date: Jun 2008
Posts: 126
Jeanette just joined TestMagic.
Slope/intercept tip

This is probably obvious to everyone except me, but if you get a slope/x-y intercept problem, first try to draw the line using the information given. Don't bother trying to solve for x and y. You will quickly be able to see if the slope is positive or negative, steep or shallow, etc. You'll also be able to make a quick estimate of where the intercepts must be.

For example, if the x-intercept equals the y-intercept and x/=/0, just a quick sketch will show you that the slope must be -1. If you're given points, plot the points and take a quick look at which direction the line is pointing.

In PP2 I had two slope questions, and the first one I wasted time trying to solve without plotting, until I realized what an easy question it is when you draw in the line.
Jeanette is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-03-2008, 06:26 PM   #2 (permalink)
geek_goddess
Eager!
 
Join Date: Jun 2008
Posts: 79
geek_goddess just joined TestMagic.
There was a PP2 QC question on slopes which I didn't interpret correctly-
The x intercept is twice the y intercept, choose which is bigger, etc -
the slope or 1/2.
I misinterpreted this by taking the modulus rather than taking the values with signs
geek_goddess is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-03-2008, 06:33 PM   #3 (permalink)
Jeanette
Got it
 
Join Date: Jun 2008
Posts: 126
Jeanette just joined TestMagic.
Quote:
Originally Posted by geek_goddess View Post
There was a PP2 QC question on slopes which I didn't interpret correctly-
The x intercept is twice the y intercept, choose which is bigger, etc -
the slope or 1/2.
I misinterpreted this by taking the modulus rather than taking the values with signs
In this problem, all you need to do is draw a line with the x intercept at 2 and the y at 1, and you see that it has a negative slope so 1/2 is bigger.
Jeanette is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-03-2008, 07:29 PM   #4 (permalink)
chestnut.cc
Wouldbegood...
 
chestnut.cc's Avatar
 
Join Date: Jun 2008
Posts: 259
chestnut.cc just joined TestMagic.
yes thats true... simply drawing out the lines often makes things much simpler... however rem that the rules for negatively sloped lines are exactly the opposite... so a flatter line has a greater slope than a steeper line if theyre both downward sloping... using a 45deg line also helps a lot... giving an idea if the slope is greater than or less than 1...
chestnut.cc is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-04-2008, 01:29 AM   #5 (permalink)
DattaPlot54321
Trying to make mom and pop proud
 
Join Date: Jun 2008
Location: Albany, NY
Posts: 12
DattaPlot54321 just joined TestMagic.
Quote:
Originally Posted by geek_goddess View Post
There was a PP2 QC question on slopes which I didn't interpret correctly-
The x intercept is twice the y intercept, choose which is bigger, etc -
the slope or 1/2.
I misinterpreted this by taking the modulus rather than taking the values with signs
I actually did this question the other day...I'm pretty sure it was asking if the slope or -1/2 was greater, and I ended up getting that they were equal.

0= ax+b
-b= ax
-b/a = x-intercept

-b/a=2b (x-intercept is twice the y-intercept)

Solve for a:
2ab=-b

a=-b/2b

a=-1/2

That's just how I did it...seemed easier to me than any kind of graphing.
DattaPlot54321 is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-04-2008, 03:25 AM   #6 (permalink)
Goldust
Let's get it on
 
Goldust's Avatar
 
Join Date: May 2008
Location: India
Posts: 291
Goldust just joined TestMagic.
I agree with DattaPlot. I prefer working with equations. Get any equation of a line in the form of y = mx + c, where m is the slope, c is the y-intercept and -c/m is the x-intercept.

I find this faster than figuring out two points on a graph and then drawing the line.
Goldust is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-04-2008, 01:15 PM   #7 (permalink)
Jeanette
Got it
 
Join Date: Jun 2008
Posts: 126
Jeanette just joined TestMagic.
Quote:
Originally Posted by Goldust View Post
I agree with DattaPlot. I prefer working with equations. Get any equation of a line in the form of y = mx + c, where m is the slope, c is the y-intercept and -c/m is the x-intercept.

I find this faster than figuring out two points on a graph and then drawing the line.

I guess we each need to do what works for us.... If you're given the information that x-intercept=y-intercept, playing around with equations is a waste of time if you just plot, say, (3,0) and (0,3). It's quite easy to see which direction the line is pointing.
Jeanette is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-05-2008, 03:17 AM   #8 (permalink)
Goldust
Let's get it on
 
Goldust's Avatar
 
Join Date: May 2008
Location: India
Posts: 291
Goldust just joined TestMagic.
Ah, but if you are given that x-intercept = y-intercept, then you would already know that the slope has to be -1 from the slope formula !
Goldust is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Old 07-05-2008, 05:43 AM   #9 (permalink)
chestnut.cc
Wouldbegood...
 
chestnut.cc's Avatar
 
Join Date: Jun 2008
Posts: 259
chestnut.cc just joined TestMagic.
you can 'see' equations as well i sup...
chestnut.cc is offline  
Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!Google Bookmark this Post!Reddit!
Reply With Quote
Reply


Thread Tools
Display Modes

What you can do
You cannot post new threads
You cannot post replies
You cannot post attachments
You cannot edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On



All times are GMT. The time now is 04:58 AM.

Contact TestMagic   TestMagic Forums      Archive   

Link to TestMagic   TestMagic Locations   Legal   Privacy

Partner Sites: GMAT Sentence Correction   SAT 2400

Content Relevant URLs by vBSEO 3.0.0
Copyright © 1998-2008 TestMagic
Ad Management by RedTyger

Scroll Up