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#12 (permalink) |
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Eager!
![]() Join Date: Dec 2006
Posts: 88
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hey chestnut....i agree wid ur method...but suppose i dont do wat u did..i.e. make num and denom relation and i assume r and s=1..main eqn. is satisfied since both sides are 0...also now dat d relation satisfies r+s=2..since d ques says least possible value , y cant 2 be d correct answer?
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