the answer is supposed to be 1/3 but can anyone explain hw..
Four cubes of same size were placed on the top of another four cubes of similar size to form a rectangular solid. Exactly one face of each cube was pained with blue.
What is the greatest fraction of the total surface area of the solid that could be blue?
(A) 1/6
(B) 3/14
(C) 1/4
(D) 2/7
(E) 1/3
Let the side of the cube be 1... Then calculate the area of the blue faces... then calculate the dimensions and area of the cuboid... if the cuboid is rectangular there is only 1 possible arrangement of 4 cubes on top of 4 cubes... ie 2*4*1... calc the total surface area of the solid... then the greatest fraction will be when all the blue faces are visible... The total surface area of the blue faces is 8*1... ie 8... the total surface area of the cuboid is 2(2*1+8*1+4*1)... ie 28... the greatest fraction that could be blue is 8/28... 2/7... DFour cubes of same size were placed on the top of another four cubes of similar size to form a rectangular solid. Exactly one face of each cube was pained with blue.
What is the greatest fraction of the total surface area of the solid that could be blue?
(A) 1/6
(B) 3/14
(C) 1/4
(D) 2/7
(E) 1/3
ok..
if yu want to solve it this way then assume each side of the small cube is a then the area of the one side will be a^2 so the area of all blue painted surface will be 8a^2...
and the total surface area of the cuboid will be 24a^2.
if all the surface painted in blue facing outside then the fraction will be 8a^2/24a^2 ... hence the answer will be 1/3..........
Last edited by mewidyu; 08-11-2008 at 06:24 AM.
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