let speed of B be x
64=96(2)-96(x)
on solving x=4/3 gal/hr...
First, calculate how long it takes to fill the drum.
2 Gallons * 32 Hours = 64 Gallons ; it takes 32 Hours.
Now, calculate the "required stream" when it takes 96 Hours:
x Gallons * 96 Hours = 64 Gallons.
X = 2/3 .
If the stream is 2 / 3 Gallons per Hour, the drum well be full in 96 Hours.
But as Flow a is 2 Gallons per Hour: 2 - 2/3 = 4/3
Good question this :
My way of looking at this problem:
The Drum would be full in 96 Hours .. (part of question)
So Inlet A would fill up how many gallons in that 96 hours? ==> 2* 96 = 192 Gallons
At the same time Outlet A would take away how many gallons? ==> x* 96 = 96x Gallons
So at this point the drum was full ie. ===> 64 Gallons
So following equation holds good :
192 - 96x = 64
Therefore x = 4/3 ..
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