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Thread: Magnetic dipole transition

  1. #1
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    There are some selection rules to this kind of transition:
    ¡÷n=0 ¡÷L=0 ¡÷S=0 ¡÷J=0,+-1 ¡÷m_j=0,+-1

    I think there is some relation to the Zeeman effect, but the selection rule of Zeeman effect is just ¡÷m_j=0,+-1 (without ¡÷J=0,+-1)

    This is all that I know. Is there any body knows more about this topics?

    Thank you.

  2. #2
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    A few more words about magnetic dipole transition:

    1. A photon with even parity and one unit of angular momentum is emitted.

    2. This kind of transition is possible only if there is a deviation from LS coupling.

    But I am not really familiar with this issue, so here I am just writing what I found in some book...

    -Yevgeny

  3. #3
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    Thank you Yevgeny!
    Yes, there is probably some deviation from LS coupling, and maybe there is why physicists characterized the effect as:

    ¡÷E=(m_j_2*g_j_2-m_j_1*g_j_1)*mu_b*B
    ¡÷m_j=0,+-1
    (of course when j=0, there is no Zeeman split), not in terms of ¡÷L and ¡÷S.

    The expression looks aweful[xx(], sorry.
    may be I rewrite it in another way:
    ¡÷E=(Jz2*g_j2-Jz1*g_j1)*mu_b*B
    ¡÷Jz=0,+-1


    But I'm not so sure, because I could not find confirmative remarks in Landau's Quantum Mechanics, and in the expression of the book, the additional energy can also be expressed in terms of L_z and S_z.


    romad

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