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Old 2009 August 13th, 08:10 PM   #21 (permalink)
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Hi Lime, I'm sorry that I didn't follow up, it's not that I dawdled but my laptop was giving me a hard time

Back to the problem. I'm not sure that I can sketch x2 - [x2] properly, specially when I first sketched [x2], I made approximations.

My question is: Is it correct to equate f(x) and g(x) and find the x then say for the values that satisfies x there's a solution?
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Old 2009 August 14th, 05:00 AM   #22 (permalink)
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You can find the solution here only by trying to imagine the graphs and their intersections.
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Old 2009 August 14th, 07:22 AM   #23 (permalink)
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Quote:
Originally Posted by lime View Post
You can find the solution here only by trying to imagine the graphs and their intersections.
Well, I sketch f(x) = x2 - floor(x2) and g(x) = (x - floor(x))2 using Excel on the interval [1,2]. I made approximations, I mean I took values for x: 1.01. 1.02, ..., 1.99,2. Take a look at the graph:
http://img27.imageshack.us/img27/6518/20254863.jpg

Is my graph correct? Does that mean we have a solution on the intersection points?
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Old 2009 August 14th, 07:36 AM   #24 (permalink)
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Besides vertical blue lines and scale on the x-axis, this seems pretty close to the truth.
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Old 2009 August 14th, 07:54 AM   #25 (permalink)
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Quote:
Originally Posted by lime View Post
Besides vertical blue lines and scale on the x-axis, this seems pretty close to the truth.
I stretched the x-axis, but I can't help with the vertical blue lines because at the end this an approximation, if x values were preciser , the lines would look more accurate.

http://img44.imageshack.us/img44/1420/73138143.jpg
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Old 2009 August 14th, 07:58 AM   #26 (permalink)
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Hint!
Code:
Plot[{x^2 - Floor[x^2], FractionalPart[x]^2}, {x, 0, 4}, 
 PlotRange -> {0, 1.5}]
in Mathematica gives http://img136.imageshack.us/img136/584/plot.gif.

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Old 2009 August 14th, 08:05 AM   #27 (permalink)
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Quote:
Originally Posted by lime View Post
Hint!
Code:
Plot[{x^2 - Floor[x^2], FractionalPart[x]^2}, {x, 0, 4}, 
 PlotRange -> {0, 1.5}]
in Mathematica gives http://img136.imageshack.us/img136/584/plot.gif.

Actually I was looking for the Matlab setup files (I used to have it) but I couldn't find it ... that's why I used Excel at the end

well ... after 25 replies we reached the answer, not bad I guess, next time I'll think twice before I mess up with math posts
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Old 2009 August 14th, 08:06 AM   #28 (permalink)
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Did we reach the answer??? I think we didn't, did we?!?
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Old 2009 August 14th, 08:10 AM   #29 (permalink)
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Did we reach the answer??? I think we didn't, did we?!?
at least I had my answer for interval [1,2].
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Old 2009 August 14th, 08:43 AM   #30 (permalink)
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Quote:
at least I had my answer for interval [1,2].
What it was?
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