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Old 2009 August 10th, 05:36 PM   #1 (permalink)
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Floor function

How many solutions has the equation below in the interval [1, 100] ?

x^2 - [x^2] = {x}^2

here [x] - floor function, {x} - fractional part.
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Old 2009 August 10th, 08:10 PM   #2 (permalink)
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Let me give it a shot:
I don't know how to put this mathmatically, I think every number has a fraction part equals to (0.5) as the difference between the square and the floor of the sqaure will be (0.25) which is (0.5)2
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Old 2009 August 11th, 04:44 AM   #3 (permalink)
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Quote:
every number has a fraction part equals to (0.5)
This is not true. For example, f(x) = {x} in interval [0;1) {x} = x.
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Old 2009 August 11th, 06:17 AM   #4 (permalink)
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but the interval of [0:1) is not part of the solution interval [1:100], right?
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Old 2009 August 11th, 06:24 AM   #5 (permalink)
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Ok. [1, 2) is a part of solution. On this interval {x} = x-1.
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Old 2009 August 11th, 06:36 AM   #6 (permalink)
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Here's another shot:
the numbers that has 0 in the units place and whatever in the fraction part ... because when those numbers are squared the fraction part is a complete square.
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Old 2009 August 11th, 06:52 AM   #7 (permalink)
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Frankly, I didn't understand what you just said. Anyway, do you have an answer?
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Old 2009 August 11th, 07:09 AM   #8 (permalink)
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Quote:
Originally Posted by lime View Post
Frankly, I didn't understand what you just said. Anyway, do you have an answer?
I meant numbers like (10.x, 20.x, etc.)
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Old 2009 August 11th, 07:13 AM   #9 (permalink)
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Apparently you're wrong. I don't know where though.

Btw. the question was asking "How many solutions ...", not "What are the numbers like ...".

Maybe you didn't understand the question?
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Old 2009 August 11th, 07:23 AM   #10 (permalink)
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Quote:
Originally Posted by lime View Post
Apparently you're wrong. I don't know where though.

Btw. the question was asking "How many solutions ...", not "What are the numbers like ...".

Maybe you didn't understand the question?
I was trying to find points where the equations has a solution then try to draw a conclusion but apparently this approach is inaccurate. I'll give it more thought before I post what I think
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