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#1 (permalink) |
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I JUST got here.
Join Date: Aug 2009
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gre 0809 #49
Help me please solve the following task
Up to isomorphism, how many additive abelian groups G of order 16 have the property that x+x+x+x=0 for each x in G ? (A) 0 (B) 1 (C) 2 (D) 3 (E) 5 Thanks in advance! |
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#2 (permalink) |
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I JUST got here.
Join Date: Sep 2009
Posts: 2
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First of all, 16 factors as 2^4, so ALL the abelian groups of order 16 are:
Z2 x Z2 x Z2 x Z2 Z4 x Z2 x Z2 Z4 x Z4 Z8 x Z2 Z16 The last two will have elements of order greater than 4, namely (1,1) in Z8 x Z2 which will be of order 8 and 1 in Z16 which is of order 16. In all the other groups, every nonzero element is of order 4 or 2 and so will satisfy x+x+x+x=0. |
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