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#3 (permalink) | |
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CHEMISTRY MAJOR
![]() ![]() ![]() Join Date: Mar 2005
Location: USA
Posts: 622
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Re: Need help!!
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![]() Here is the right place for this, because dealing with this problem requires knowledge beyond the high-school level (hence, in my humble opinion ).
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Per aspera ad astra Profile: http://www.urch.com/forums/showthread.php?t=27018&highlight=chemistry |
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#4 (permalink) |
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Trying to make mom and pop proud
Join Date: Mar 2005
Posts: 13
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Re: Need help!!
quiza,
Here, a(n)=2^n.x^n/n! => a(n+1)=2^(n+1).x^(n+1)/(n+1)! So, |a(n+1)/a(n)|=|2x/(n+1)| For convergence cosider limit x->infinity|a(n+1)/a(n)|=limit x->infinity|2x/(n+1)|=0 =>The series converges for all the +ve values of x and radius of convergence is infinity |
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#5 (permalink) | |
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Non-analytic Shaman! ;)
![]() ![]() ![]() ![]() Join Date: Oct 2004
Posts: 1,607
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Re: Need help!!
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I totally agree. This thread was in the Lounge earlier. Perhaps I should have clarified that by GRE-Math, I meant GRE-(Subject-test)-Mathematics. |
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#6 (permalink) | |
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Socratic realist
![]() ![]() Join Date: Feb 2005
Location: Georgia, USA
Posts: 220
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Re: Need help!!
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#8 (permalink) |
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Trying to make mom and pop proud
Join Date: Mar 2005
Posts: 13
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Re: Need help!!
Dragonfinity,
limit x->infinity was typing mistake,I am agree with you and infact it is limit n->infinity. But please explain how the series converges for -ve values too? Thanks for rectification and comments |
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