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Amit28it

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I am trying to simplify the following equation:

 

[3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)]

 

This is how I'm processing it:

 

[3x + 6 + 2x] - [4y + 8 - 3y + 6]

[5x + 6] - [14 + y]

5x + 6 - 14 + y = 5x + y -8

 

However, the text gives the answer as:

 

5x - y - 8

 

So what am I doing wrong? Thanks.

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When you reached here:

 

[5x + 6] - [14 + y]

5x + 6 - 14 + y = 5x + y -8

 

You did not distribute the negative one to y.

 

So, it should be:

 

5x + 6 - 14 - y = 5x - y -8

 

Can you explain it in broad way ????????

Plz it will help me in solving other questions.

Thanks .

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I'll try my best Herr or Frau Amit.

 

[3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)]

 

First we do our order of operations:

______________

Parenthesis

Exponents

M-D: multiplication and division

A-S: addition and subtraction

______________

 

So, in our equation: [3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)] , we have P, M, and A-S

 

First tackle the parenthesis'

 

[3(x + 2) + 2x]

 

Distribute 3 to (x+2) by multiplication and end up with:

 

[3x+6+2x].

 

Same Here:[4(y + 2) - 3(y - 2)]. Distrubte 4 to (y+2) and 3 to (y-2) by multiplication and receive:

 

[(4y+8)-(3y-6)] But notice the negative in front of (3y-6). You should treat it as -1(3y-6) //this is where you messed up.

 

so distribute -1 to (3y-6) by multiplication and get:

 

[(4y+8)+(-3y+6)]

______________

 

Now we do addition (or subtraction) of like terms:

 

[3x+6+2x] 3x and 2x are like terms so add.

 

[5x+6]

 

Now [(4y+8)+(-3y+6)]: 4y and -3y are like terms, add. 8 and 6 are like terms, add.

 

[y+14]

________

 

Now we do the final calculation:

 

[5x+6]-[y+14] : Notice you have that pesky negative infront of [y+14] again. treat it as -1(y+14)

 

distrubte -1 to (y+14) by multiplication

 

[-y-14]

 

add like terms

 

5x-y-8

 

If I did not explain it well, please tell me which part. or if you would like another example.

 

Enjoy, or don't

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  • 9 months later...

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