Amit28it Posted November 10, 2011 Share Posted November 10, 2011 I am trying to simplify the following equation: [3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)] This is how I'm processing it: [3x + 6 + 2x] - [4y + 8 - 3y + 6] [5x + 6] - [14 + y] 5x + 6 - 14 + y = 5x + y -8 However, the text gives the answer as: 5x - y - 8 So what am I doing wrong? Thanks. Quote Link to comment Share on other sites More sharing options...
Architect Posted November 12, 2011 Share Posted November 12, 2011 When you reached here: [5x + 6] - [14 + y] 5x + 6 - 14 + y = 5x + y -8 You did not distribute the negative one to y. So, it should be: 5x + 6 - 14 - y = 5x - y -8 Quote Link to comment Share on other sites More sharing options...
Amit28it Posted November 14, 2011 Author Share Posted November 14, 2011 When you reached here: [5x + 6] - [14 + y] 5x + 6 - 14 + y = 5x + y -8 You did not distribute the negative one to y. So, it should be: 5x + 6 - 14 - y = 5x - y -8 Can you explain it in broad way ???????? Plz it will help me in solving other questions. Thanks . Quote Link to comment Share on other sites More sharing options...
Architect Posted November 15, 2011 Share Posted November 15, 2011 I'll try my best Herr or Frau Amit. [3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)] First we do our order of operations: ______________ Parenthesis Exponents M-D: multiplication and division A-S: addition and subtraction ______________ So, in our equation: [3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)] , we have P, M, and A-S First tackle the parenthesis' [3(x + 2) + 2x] Distribute 3 to (x+2) by multiplication and end up with: [3x+6+2x]. Same Here:[4(y + 2) - 3(y - 2)]. Distrubte 4 to (y+2) and 3 to (y-2) by multiplication and receive: [(4y+8)-(3y-6)] But notice the negative in front of (3y-6). You should treat it as -1(3y-6) //this is where you messed up. so distribute -1 to (3y-6) by multiplication and get: [(4y+8)+(-3y+6)] ______________ Now we do addition (or subtraction) of like terms: [3x+6+2x] 3x and 2x are like terms so add. [5x+6] Now [(4y+8)+(-3y+6)]: 4y and -3y are like terms, add. 8 and 6 are like terms, add. [y+14] ________ Now we do the final calculation: [5x+6]-[y+14] : Notice you have that pesky negative infront of [y+14] again. treat it as -1(y+14) distrubte -1 to (y+14) by multiplication [-y-14] add like terms 5x-y-8 If I did not explain it well, please tell me which part. or if you would like another example. Enjoy, or don't Quote Link to comment Share on other sites More sharing options...
TommyRiordan Posted September 14, 2012 Share Posted September 14, 2012 [3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)] = [ 3x + 6 - 4y - 8 - 3y + 6] = [ 3x -7y +4] Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.