720 Q: 49 (90%) V40 (91%)

[vreddy]

well, the red chair makes it distinguishable. In circular permutation, relative positions are *indistinguishable*

[Bart]

Originally posted by TargetMBA

This was a circular permutation. i.e. the 5 chairs are arranged to form a circle e.g. around a table (instead of a row). Then I think the answer should be less than 4!.

In that case, the circular portion of the 4 (non-red) chairs is equivalent to a row of 4 (non-red) chairs since the one and only red chair has a specific place in the circle. Therefore, the answer remains 4! = 24.

[TargetMBA]

Just got the official score. Scored 6.0 in AWA. I have posted few topics in AWA section. Hope they will be useful! Thanks