Hi all ,
Can you please help me in soving the problem?
Find out the amount of zinc sulfate needed in the rx?
Aq.sol. zinc sulfate 0.5%
Aq.sol. boric acid 1.0% aa-10 ml
Normal saline sol.qs ad- 30 ml
Answer: 50 mg
Thanks.
-
Hi all ,
Can you please help me in soving the problem?
Find out the amount of zinc sulfate needed in the rx?
Aq.sol. zinc sulfate 0.5%
Aq.sol. boric acid 1.0% aa-10 ml
Normal saline sol.qs ad- 30 ml
Answer: 50 mg
Thanks.
-
Last edited by knok; 07-11-2008 at 06:23 PM. Reason: Textese: u, (?)
Hi,
In the question they have given aq zinc sulphate soln and aq boric acid solution aa 10 ml which means of each 10 ml.So calculate aq zinc solution 0.5% in 10 ml
100 ml contains 0.5 gms of zinc sulphate
Then 10 ml contains 0.05 gms of zinc sulphate(0.05 gms is same as 50 mg which is the answer)
Hi all ,
another problem , can anyone please solve this one
How many ml of low alcohol elixir (10%) and high alcohol elixir (78%) must be mixed for the following Rx:
codiene phosphate : 0.4 g
Alcohol elixir 38% - 50 ml
Pur.water qs - 100 ml
thanks...
Hi hems,
Thanks for thy reply , but i have doubt why isnt Normal saline considered while calculating and only boric soln vol is considered?
Thanks
Hi hems,
Thanks for thy reply , but i have doubt why isnt Normal saline considered while calculating and only boric soln vol is considered?
Thanks
Last edited by coolmist528; 12-20-2005 at 05:25 PM. Reason: Automerged post
You need to do alligations for this problem:
78| | 28
| 38 |
10| | 40
68 total
so basically you need 28 parts of the 78%, and 40 parts of the 10% to get 68 parts of the 38%.
28mL/68mL x 50mL= 20.6mL of the 78%
40mL/68mL x 50mL= 29.4mL of the 10%
Hope this is right.
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Last edited by knok; 07-11-2008 at 06:24 PM. Reason: Capital letters
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