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sabna
11-24-2004, 11:38 AM
Hi..friends!!!!
can anyone help me with this Q..?

please see the attachment!!!!

prayers
sabna

lorcar
11-24-2004, 12:44 PM
nice question!

At the first, it seems that the x coordinate of the point is 4 (and i still believe it is!): so the question becomes
4 vs 4.26 --------> B

BUT
second approach
Since the line is 45 degrees.....
we can consider 6 as the Hypotenuse of the right equilateral triangle with the 2 legs equal to the x=y coordinates

We know (by ETS math review) that in this case the

hypotenuse= leg* SQRT(2)
in our case then

6= x * SQRT(2) ------> x= 6/SQRT(2) (AND THIS IS COLUMN A)

comparing now
6/SQRT(2) vs 3*SQRT(2)

I would say C !!!!

hope somebody would solve this....

thebullfighter
11-24-2004, 01:04 PM
to start with, as line passes from 0,0 & has slope angle as 45egree. X-coordinate & Y-coordinate of any pt. on the line gotta be same, ie, for x=1, y= 1, for x=2, y=2 and similarly.

so, in our case, condidering the right-angled triangle,
6^2 = x^2 + y^2
or, 36 = 2* x^2
or, x^2 = 18
or, x = 3 sqrt2 (<--- note, we are dealing with sides of triangle, also workin in th 1st quad.)

hence, Col. A = Col. B

sabna
11-24-2004, 02:12 PM
Yeaaaaaah!!!

right bull..!!!!..lorcar, both of u have done it..!!!!
but lorcar's first approach was wrong..!!
thanks guys!!!!!!

prayers
sabna

lorcar
11-24-2004, 02:41 PM
BUT i thought the answer was D, since it was highligthed!!!!

PINTUDAO
11-24-2004, 07:50 PM
People it is so difficult. I don't know I prefer toefl :tup:

but in our case keeping studying BYE