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Nosheen
01-04-2004, 01:15 PM
Could somebody PLEASE tell me a fast way of solving this: Itís a Quantitative Comparison (from PowerPrep)

S is the set of all integers from 1 to 48, inclusive
V is the sum of all of the even integers
D is the sum of all of the odd integers in S

Column A: V

Column B: D + 23


The correct answer is: The Quantity in column A is greater.


Thanks!!

carlosdaniel
01-08-2004, 03:09 PM
Hi. I understand that V is the sum of all even integers "IN S". Therefore:
V = 2 + 4 + 6 + ... + 48
D = 1 + 3 + 5 + ... + 47
In this order, each number in V is greater than the corresponding number in D by 1. For example 2 is one more than 1, 4 is one more than 3 and so on. Considering that V has 24 elements, their sum is 24 more than D.
Thus V=D+24, which is greater than D+23.
The answer is A.
Hope it heps.