ak78 Posted November 19, 2004 Share Posted November 19, 2004 I know the answer, and I got the right answer, but I simply forgot some of the algebra that would allow me to get there. Can someone detailedly go through the algebra of this problem? I get the combining like terms part, and also get up to the part of getting a(b+c) + d(b+c) = 6. It's the just rest that where I get kind of hazy. And I'm writing this from memory, so I'm not quite sure if statement is really supposed to equal 6 or not. But I'm guessing that the actual numerical doesn't matter so much. What is the value of b+c?(1) ab+cd+ac+bd = 6 (2) a + d = 4 Quote Link to comment Share on other sites More sharing options...
spiderman Posted November 19, 2004 Share Posted November 19, 2004 (1) a(b+c) + d(b+c) = 6 take (b+c) out (b+c) * (a+d) = 6. (2) (a+d) = 4 combining 1 and 2, b+c = 6/4 Quote Link to comment Share on other sites More sharing options...
fighter Posted November 19, 2004 Share Posted November 19, 2004 Hello I am new to this group. Even I tried the same way mentioned by Mr Spiderman Quote Link to comment Share on other sites More sharing options...
gmatguy Posted November 19, 2004 Share Posted November 19, 2004 C it is Quote Link to comment Share on other sites More sharing options...
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