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    An Urch Guru Pundit Swami Sage hitzs's Avatar
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    even or not

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    11. Is x an even integer?
    (1) x is the square of an integer.
    (2) x is the cube of an integer.

    To me it seems that its C ...but wanted to know if smthing else
    Lets do it !!!

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    An Urch Guru Pundit Swami Sage 800Bob's Avatar
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    It's E. Taking both statements together, x could be 1, in which case the answer to the question is no. Or x could be 64, in which case the answer to the question is yes. Two different answers to the question... insufficient. (In fact, any number that is the 6th power of an integer will satisfy both statements. x could be 1^6, 3^6, 5^6, etc. -- all odd. Or x could be 2^6, 4^6, 6^6, etc. -- all even.)

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    An Urch Guru Pundit Swami Sage hitzs's Avatar
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    Thanx Bob !! damn I missed 1 ):
    Lets do it !!!

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    Eager!
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    1 and 0 also dissprove it.

    1^2 = 1^3 = 1 = odd
    0^2 = 0^3 = 0 = even

    is that logic ok?

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    An Urch Guru Pundit Swami Sage
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    11. Is x an even integer?

    (1) x is the square of an integer.

    int = 3, so x=9, and x is not even
    int = 2, so x=4, and x is even
    (insuff) BCE

    (2) x is the cube of an integer.
    int = 3, so x=27, and x is not even.
    int = 2, so x=8, and x is even
    (insuff) CE

    (T) int = 1, so (1) x = int^2 = 1, and (2) x = int^3 = 1, and x is not even
    int = 0, so (1) x = int^2 = 0, and (2) x = int^3 = 0, and x is even

    or follow 800Bob's logic
    if x=64, then (1) int=8, and (2) int=4, and x is even
    if x=1, then (1) int=1, and (2) int=1, and x is not even
    (insuff),

    Answer E.
    Last edited by lawrencl; 02-13-2006 at 07:00 PM. Reason: Automerged post

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