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# Thread: even or not

1. ## even or not

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11. Is x an even integer?
(1) x is the square of an integer.
(2) x is the cube of an integer.

To me it seems that its C ...but wanted to know if smthing else  Reply With Quote

2. It's E. Taking both statements together, x could be 1, in which case the answer to the question is no. Or x could be 64, in which case the answer to the question is yes. Two different answers to the question... insufficient. (In fact, any number that is the 6th power of an integer will satisfy both statements. x could be 1^6, 3^6, 5^6, etc. -- all odd. Or x could be 2^6, 4^6, 6^6, etc. -- all even.)  Reply With Quote

3. Thanx Bob !! damn I missed 1 ):  Reply With Quote

4. 1 and 0 also dissprove it.

1^2 = 1^3 = 1 = odd
0^2 = 0^3 = 0 = even

is that logic ok?  Reply With Quote

5. 11. Is x an even integer?

(1) x is the square of an integer.

int = 3, so x=9, and x is not even
int = 2, so x=4, and x is even
(insuff) BCE

(2) x is the cube of an integer.
int = 3, so x=27, and x is not even.
int = 2, so x=8, and x is even
(insuff) CE

(T) int = 1, so (1) x = int^2 = 1, and (2) x = int^3 = 1, and x is not even
int = 0, so (1) x = int^2 = 0, and (2) x = int^3 = 0, and x is even

or follow 800Bob's logic
if x=64, then (1) int=8, and (2) int=4, and x is even
if x=1, then (1) int=1, and (2) int=1, and x is not even
(insuff),

Answer E.  Reply With Quote

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