Let M - number of males, F - number of females
Need to compare (M+F)/2 and 0,55F+0,35M given that F = M+20
(M + M + 20)/2 compare with 0,55(M +20) + 0,35M
(2M+20)/2 compare with 0,55M+0,35M+11
M+10 < M+11, thus (2) is sufficient !
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