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Thread: Any simpler way of reducing fractions?

  1. #1
    Eager!
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    Any simpler way of reducing fractions?

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    Reduce 128352 to its lowest terms.
    238368
    A.
    3
    4
    B.
    5
    13
    C.
    7
    13
    D.
    9
    13


    Is there are a simple way to reduce such huge fractions?

  2. #2
    Preparing ! 800's Avatar
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    Yes. Guessing !
    Consider the full fraction as 12.83K / 23.83K ~ 13/24 . it is ROUGHLY half.
    eliminate A (one third)
    eliminate B (~one third)
    eliminate D (> two third)
    we left with C.
    HTH
    Dont think about the difficulty, Just get it right !
    If my post is helpful, click "+" button. Lets inspire each other !!!

  3. #3
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    Hi 800!

    Looks good method! Thanks ... are there any more thoughts that from other members who have come across such problems.

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    Within my grasp! sandeep_chads's Avatar
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    I think averaging is the nest method to solve long fractions
    Hey Harvard, I am right here!!
    rep me if I made some sense

  5. #5
    An Urch Guru Pundit Swami Sage
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    Common Sense Trumps All

    Quote Originally Posted by vd17 View Post
    Hi 800!

    Looks good method! Thanks ... are there any more thoughts that from other members who have come across such problems.
    When you are faced with a problem that seems to require a whole lot of number crunching, then the "trick" to such a problem is usually figuring out how to avoid the number crunching.

    What I did in this case was look at the numerator and denominator and chop off all but the highest digit of the smaller number (in this case they have the same number of digits).

    128352 -> 1
    238368 -> 2

    So, anything not even close to 1/2 can be safely eliminated: A and D can go, which leaves B and C

    Need more precision? Add one digit back to the end of each estimate

    12/23

    Since 12 is more than half of 23, let's see whether only one of the remaining choices is greater than 1/2 -> That leaves C

    done

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