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Thread: Mathematics - a new basis

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    Mathematics - a new basis

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    See a picture that represents the relations of the two triangles
    Mathematics - a new basis-matematicka-zagonetka.jpg
    what is a "?"
    3?3=3
    3?3=4
    3?3=5
    3?3=6
    3?3=7
    3?3=8
    3?3=9
    3?3=10
    3?3=12

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    there is no solution in the current mathematics :
    1.3+[0]3=3
    2.3+[1]3=4
    3.3+[2]3=5
    4. 3+[3]3=6 or 3+3=6
    5.33Rd1(6)d2(7)+3=7
    6.33Rd1(6)d2(8 )+3=8
    7.33Rd1(6)d2(9)+3=9
    8.33Rd1(6)d2(10)+3=10
    9.33Rd1(6)d2(12)+3=12
    (1,2,3,4) - there are several types of addition in the set N
    (5,6,7,8,9) - that there are dynamic numbers, where this can add

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    1 Mathematics Space
    We'll tell mathematical space with two initial geometric object that can not
    prove.
    1.Natural geometric object - natural along .
    2.Real geometric objects - real alongs .
    1.1 Natural along
    In the picture there is a natural geometric object along (AB), it has a beginning (A)
    and end (B) - this property natural long'll call point.


    Mathematics - a new basis-w1.png


    1.2 The basic rule
    Two (more) natural longer are connected only with points.

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    2 Natural Mathematics
    2.1,along , one-way infinite along the (semi-line) "1"
    "1"-from any previous evidence (axioms), a new proof
    Theorem-Two (more) natural longer merge points in the direction of the first AB
    longer natural.


    EVIDENCE - Natural long (AB, BC) are connected - we get along AC.


    Mathematics - a new basis-w2.png


    Natural long (AB, BC, CD) are connected - we get along AD.


    Mathematics - a new basis-w3.png


    Natural long (AB, BC, CD, DE) are connected - we get along AE.


    Mathematics - a new basis-w4.png
    ...


    Natural long (AB, BC, CD, DE, ...) are connected - getting the sim-
    measurement along the infinite.
    www5.png


    Mathematics - a new basis-w5.jpg

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    2.2 Numeral along, numeric point "2.1"
    Theorem-character mark points on the one-way infinite
    long (A, B, C, ...), replace the labels {(0), (0.1), ..., (0,1,2,3,4,5,6,7,8,9 ), ...}
    which are set circular and positionally.


    Proof - is obtained by numerical along which the numerical point of {(0,00,000,
    0000, ...), (​​0,1,10,11,100,101, ...), ..., (0,1,2,3,4,5,6,7,8,9,10,11, 12, ...), ...}.
    Mathematics - a new basis-w6.jpg

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    2.3 Natural numbers "2.2"
    Theorem - There is a relationship (length) between Point in numeric (0) and
    all points along the numerical.


    Proof - Value (length) numeric point (0) and numerical point (0)
    the number 0


    Mathematics - a new basis-w7.png


    Ratio (length) numeric point (0) and the numerical point of (1) the number o1


    Mathematics - a new basis-w8.png

    Ratio (required) numeric point (0) and numeric item (2) is the number 2


    Mathematics - a new basis-w9.png


    Ratio (length) numeric point (0) and the numerical point of (3) is the number 3


    Mathematics - a new basis-w10.png


    Ratio (length) numeric point (0) and the numerical point of (4) is the number 4


    Mathematics - a new basis-w11.jpg
    ...
    Set - all the possibilities given theorem.
    The set of natural numbers N = {0,1,2,3,4,5,6,7,8,9,10,11,12, ...}.

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    2.4 Mobile Number "2.2,2.3"
    Theorem-Natural numbers can be specified and other numerical
    point other than the point numeric 0th
    Proof - Value (length) numeric point (0) and numeric point (2)
    the number 2


    Mathematics - a new basis-w12.jpg


    Ratio (length) numerical point (1) and the numerical point of (3) is the number 2


    Mathematics - a new basis-w13.jpg


    Ratio (length) numerical point (2) and the numerical point of (4) is the number 2




    Mathematics - a new basis-w14.jpg
    ...
    A set of mobile numbers Nn = {[n]N}

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    I am a bit confused... Nine if this looks GMAT related. What is the purpose?

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