# Thread: Mathematics - a new basis

1. ## Mathematics - a new basis

See a picture that represents the relations of the two triangles what is a "?"
3?3=3
3?3=4
3?3=5
3?3=6
3?3=7
3?3=8
3?3=9
3?3=10
3?3=12  Reply With Quote

2. there is no solution in the current mathematics :
1.3+3=3
2.3+3=4
3.3+3=5
4. 3+3=6 or 3+3=6
5.33Rd1(6)d2(7)+3=7
6.33Rd1(6)d2(8 )+3=8
7.33Rd1(6)d2(9)+3=9
8.33Rd1(6)d2(10)+3=10
9.33Rd1(6)d2(12)+3=12
(1,2,3,4) - there are several types of addition in the set N
(5,6,7,8,9) - that there are dynamic numbers, where this can add  Reply With Quote

3. 1 Mathematics Space
We'll tell mathematical space with two initial geometric object that can not
prove.
1.Natural geometric object - natural along .
2.Real geometric objects - real alongs .
1.1 Natural along
In the picture there is a natural geometric object along (AB), it has a beginning (A)
and end (B) - this property natural long'll call point. 1.2 The basic rule
Two (more) natural longer are connected only with points.  Reply With Quote

4. 2 Natural Mathematics
2.1,along , one-way infinite along the (semi-line) "1"
"1"-from any previous evidence (axioms), a new proof
Theorem-Two (more) natural longer merge points in the direction of the first AB
longer natural.

EVIDENCE - Natural long (AB, BC) are connected - we get along AC. Natural long (AB, BC, CD) are connected - we get along AD. Natural long (AB, BC, CD, DE) are connected - we get along AE. ...

Natural long (AB, BC, CD, DE, ...) are connected - getting the sim-
measurement along the infinite.
www5.png   Reply With Quote

5. 2.2 Numeral along, numeric point "2.1"
Theorem-character mark points on the one-way infinite
long (A, B, C, ...), replace the labels {(0), (0.1), ..., (0,1,2,3,4,5,6,7,8,9 ), ...}
which are set circular and positionally.

Proof - is obtained by numerical along which the numerical point of {(0,00,000,
0000, ...), (​​0,1,10,11,100,101, ...), ..., (0,1,2,3,4,5,6,7,8,9,10,11, 12, ...), ...}.   Reply With Quote

6. 2.3 Natural numbers "2.2"
Theorem - There is a relationship (length) between Point in numeric (0) and
all points along the numerical.

Proof - Value (length) numeric point (0) and numerical point (0)
the number 0 Ratio (length) numeric point (0) and the numerical point of (1) the number o1 Ratio (required) numeric point (0) and numeric item (2) is the number 2 Ratio (length) numeric point (0) and the numerical point of (3) is the number 3 Ratio (length) numeric point (0) and the numerical point of (4) is the number 4 ...
Set - all the possibilities given theorem.
The set of natural numbers N = {0,1,2,3,4,5,6,7,8,9,10,11,12, ...}.  Reply With Quote

7. 2.4 Mobile Number "2.2,2.3"
Theorem-Natural numbers can be specified and other numerical
point other than the point numeric 0th
Proof - Value (length) numeric point (0) and numeric point (2)
the number 2 Ratio (length) numerical point (1) and the numerical point of (3) is the number 2 Ratio (length) numerical point (2) and the numerical point of (4) is the number 2 ...
A set of mobile numbers Nn = {[n]N}  Reply With Quote

8. I am a bit confused... Nine if this looks GMAT related. What is the purpose?  Reply With Quote