I get A as the answer. Maybe..I maybe making a mistake in adding the numbers....so I will check and post my response.
Ann, Bob, Chris, Dana, and Eric are different ages such that their average age is 16. Bob is twice as old as Ann was three years ago. Eric is nine years younger than Bob. The sum of Chris and Ann's ages is equal to twice Dana's age. Dana is one year older than Ann. How old is Eric?
A) 13
B) 14
C) 15
D) 22
E) 23
Can some one help Solve this problem
SPOILER: B
I get A) 13
sorry for the long winded solution:
A = Ann
B = Bob
C = Chris
D = Dana
E = Eric
(A+B+C+D+E)/5 = 16 , Therefore total age = 80
B=2(A-3)
E=B-9
C+A = 2D
D= A+1
What is age of E?
A + B + C + D + E = 80
relate each age in terms of A:
B = 2A - 6
C+A = 2(A+1)
C+A=2A+2
C=A+2
E = (2A-6) -9
E = 2A-15
A+B+C+D+E =
A + (2A - 6) + (A+2) + (A+1) + (2A-15) = 80
7A = 98
A = 14
If A = 14 Then B = 22 And E = 13
Eric is 13 years old.
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