M3 Posted September 29, 2005 Share Posted September 29, 2005 Hello everyone,:) I'm a new one in this forum. This forum looks pretty informative to me. Trying to ask your favor...Is anybody who can solve the following? I'm trying to solve the following. There are "n" bulbs wired in line so that if any one bulb is dead, all "n" bulb will not light up accordingly. Assuming a probability "p" that one bulb is blown or dead, what is a probability that all "n" bulbs will not light up? The probability "p" is equivalent to all "n" bulbs. Thanks!! Quote Link to comment Share on other sites More sharing options...
chix475ntu Posted September 30, 2005 Share Posted September 30, 2005 totoal probability that all bulbs are not blown away is (1-p) ^ n ... so probability that atleast one blown away = total probability that all bulbs are blown away = 1 - (1-p)^n Quote Link to comment Share on other sites More sharing options...
adcambridge Posted September 30, 2005 Share Posted September 30, 2005 Agree with Chix prob that one bulb is not blown is (1-p)...n buls are not blown will be (1-p)*(1-p)*....ntimes =(1-p)^n the bulbs will not lightup if atleast one of the bulbs is blown up..so atleast one blown up= 1-prob of none blown up = 1-(1-p)^n Quote Link to comment Share on other sites More sharing options...
M3 Posted September 30, 2005 Author Share Posted September 30, 2005 Thanks a lot guys! :) Both of your solutions make sense to me. I really appreciate it! I was not 100% sure but now I'm 100% confident! Quote Link to comment Share on other sites More sharing options...
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