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vijay1311

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Can anyone explain the below problem??

 

Solution A is 20% salt and solution B is 80 % salt. If you have 30 ounces of solution A and 60 ounces of solution B in what ratio could you mix solution A with solution B to produce 50 ounces of a 50% solution?

 

a)6:4

b)6:14

c)4:4

d)4:6

e)3:7

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30 ounces A --> 6 ounces of salt

 

60 ounces B --> 48 ounces of salt

 

x= amt of A taken to make final solution

y= amt of B taken to make final solution

 

Final solution to have 25 ounces salt.

 

x+y=50

0.2x + 0.8y = 125

 

x=25, y=25

so 1:1 or 4:4

 

the info "If you have 30 ounces of solution A and 60 ounces of solution B" seems to be redundant

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The official answer is 4:4. I got confused by the redundant information.Thanks a lot

 

This is how I did it:

 

(0.20A + 0.80(50-A))/50 = 0.50

 

0.20A + 40 -0.80A = 25

 

0.60A = 15

 

A= 15(10/6)

 

A = 25

 

Mixture contains 50 grams so B = 25. 25/25 = 1

 

 

-CPhD

Edited by canadian phd
I'm an idiot
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vijay1311, you're killing me! I just spent that last 20 minutes of my morning trying to get my answer to match one of your posted choices. I write the GMAT on July 26th so it was freaking me out that I couldn't get a simple problem like this. Anyway, thanks for the clarification.

 

This is how I did it:

 

(0.20A + 0.80(50-A))/50 = 0.50

 

0.20A + 40 -0.80A = 25

 

0.60A = 15

 

A= 15(10/6)

 

A = 25

 

Mixture contains 50 grams so B = 25. 25/25 = 1

 

 

-CPhD

 

hey..i did'nt get you....did my post help you or not....the answer choice 4:4 is already mentioned in the multiple choices..

All the best for your exam..Do brief me about the exam once you finish your exam...i am planning to take the test at the end of august..Thank you

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