1. ## Median

The average of 5 positive numbers a b c d and e is 16 and a<b<c<d<e if e is 40. what is the greatest possible value of median of 5 integers
a) 16 b) 18 c) 19 d) 20 e) 22  Reply With Quote

2. The answer should be 19 that is option c.
Median is the middle number, thus the median in this case is C.
16 X 5 = 80.

E is 40 thus a+b+c+d= 40. In order for C to have the largest possible value we make C less than d but very close to d, Thus the answer is 19.  Reply With Quote

3. so we will maximize the median or C, by minimizing the rest of the numbers we'll make a=1 and b=2 (because of the inequality none of them will be the same). We'll make c=x and then d=x+1. We know already that e is 40
The average of the 5 numbers = 16, which means that the sum of all 5 numbers = 80, thus 1+2+x+x+1+40=80 or 2x+44=80 or x=18  Reply With Quote

4. ## Re: Median

There are 5 numbers it says, not 6, so 1+1+x+x+40=5*16 --> 2x = 38 --> x =19 option C. Personally, I would just plug numbers, it's a lot faster.  Reply With Quote

5. ## Re: Median

18. The strict inequalities matter  Reply With Quote

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