ak78 Posted November 19, 2004 Share Posted November 19, 2004 A store currently charges the same price for each towe that it sells. If the current price of each towel were to be increased by $1, 10 fewer of the towels could be bought for $120, excluding sales tax. What is the current price of each towel? (A) $1 (B) $2 © $3 (D) $4 (E) $12 I don't understand the phrase "10 fewer of the towels could be bought for $120" so this one completely threw me off. (Taken from PowerPrep CAT 2) Quote Link to comment Share on other sites More sharing options...
riteshb Posted November 19, 2004 Share Posted November 19, 2004 I actually worked backwards using the answer choices instead of using an equation. At $3, you can buy 40 towels right? Now if the price is increased to $4, you can buy 30 towels now for $120. Quote Link to comment Share on other sites More sharing options...
shaq Posted November 19, 2004 Share Posted November 19, 2004 Yes Ritesh's method is the shortcut. The long method is .. let number of towels bought for $120 = n so price of a single towel = $ 120 / n now price of 1 towel increases by $ 1 so new price of a single towel = $ (120 / n) + 1 no. of towel that could be bought at this price = n - 10 so new price of a single towel = $ 120 / (n -10) so equating so (120/n) + 1 = 120 / (n - 10) (120 + n) / n = 120 / (n - 10) n^2 -10n - 1200 = 0 (n-40)(n+30) = 0 n = 40 or n = -30 n= 40 = number of towels that could be bought at current price. => current price per towel = $ 120 / 40 = $ 3 so ans is C Quote Link to comment Share on other sites More sharing options...
gmatguy Posted November 19, 2004 Share Posted November 19, 2004 ya even i use the plugging in method .. its 3 Quote Link to comment Share on other sites More sharing options...
thatchanon Posted December 14, 2004 Share Posted December 14, 2004 [clap] [clap] [clap] [clap] [clap] [clap] Quote Link to comment Share on other sites More sharing options...
thatchanon Posted December 14, 2004 Share Posted December 14, 2004 Soory guy, I confused this question with another one in my test. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.