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Thread: The practice paper based test on the ets website

  1. #11
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    One more correction in this answer.

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    For the question , In the XY plane, find the following,
    (c) The Y intercept of a line with slope 3 that passes through the point (-2,1)
    From the Ques, we can say Y= 3x+b Now plug in the value (-2,1) ,
    1= 3( -2) + b
    1+6 = b
    7= b ( Thats the answer for the C )
    So, y = 3x -7 is the equation
    Now coming to the (d) The x- intercept of the graphs in (a),(b),(c)
    X- intercept means y=0
    (a) 2y+x= 6
    Since Y= 0, x= 6(thats the answer)
    (B) Y=X/3 +1
    Since Y=0, X= -3(thats also the answer)
    (c) Y= 3x-7
    Since Y= 0, x= -7/3 (also te answer)

  2. #12
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    Question Re: The practice paper based test on the ets website

    I have a quick question about D.


    Quote Originally Posted by twohundredping View Post
    18. Answered in your other thread
    19.
    (a) We can put the equation in slope intercept form where it is easy to see the slope and y-intercept.
    Slope intercept form: y = m*x + b, where m is the slope and b is the y-intercept
    2y + x = 6
    2y = 6 - x
    y = 3 - x/2 = -x/2 + 3 = -1/2 * x + 3

    Therefore, the slope is -1/2 and the y-intercept is 3.

    (b) Here they gave us one point (3, 2) and told us the y-intercept is 1. There are two approaches we can use to solve the problem from here.

    Approach 1:
    y = m*x + b
    Since the y-intercept is 1, b = 1
    y = m*x + 1
    Now we can plug in the point (3,2) for x and y.
    2 = m * 3 + 1
    1 = 3m
    m = 1/3
    So the equation of the line is:
    y = 1/3 * x + 1

    We can plug in the point (3,2) to verify that we did everything correctly

    Approach 2:
    Since the y-intercept is 1, we know that b = 1 and that the point (0, 1) is on the line.
    Now we can find the slope between (3,2) and (0,1) as:
    (2 - 1) / (3 - 0) = 1/3
    Now we can give the equation of the line as:
    y = 1/3 * x + 1

    We can plug in the point (3,2) to verify that we did everything correctly

    (c) y = 3 * x + b
    Now plug in the point they give you.
    1 = 3 * 2 + b
    -5 = b
    So y = 3 * x - 5 is the equation of the line.

    (d) The x-intercept is the point where y = 0.
    x-intercept of (a): 2x + 0 = 6
    x = 3 is the x-intercept

    x-intercept of (b): 0 = 1/3 * x + 1
    -1 = 1/3 * X WHat did you do here to get -3?
    x = -3 is the x-intercept Can you help me understand how you got this -3?

    x-intercept of (x): 0 = 3 * x - 5
    5 = 3 * x
    x = 5/3 is the x-intercept

  3. #13
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    Re: One more correction in this answer.

    on D, part B....how did you get -3? I cant figure it out

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