mav32 Posted August 24, 2011 Share Posted August 24, 2011 1. A B Max surface area covered by 4 Max surface area covered by 1 place mat with circular place mats with radius R radius 2r. 2. [] = absolute value A B [a+b+c] [a]++[c] 3. 4-1/x = 4x I thought I did this one right but for some reason my answer is not coming out right. Thanks for the help everyone!!!!!!! Quote Link to comment Share on other sites More sharing options...
mav32 Posted August 24, 2011 Author Share Posted August 24, 2011 i apologize for question 1. It is supposed to be separated. 4 place mats radius r and 1 place mat radius 2r. Sorry Quote Link to comment Share on other sites More sharing options...
hekopeko Posted August 27, 2011 Share Posted August 27, 2011 hey , am just beginner in math , but i have an idea about third question what was your answer , 3/4 , or what , here is how this come with me 4-1 4x ___ = ___ x 1 then we can use multiplying method and yield 4x = 4-1 then 3/4 maybe am wrong , you have to search more Quote Link to comment Share on other sites More sharing options...
Riyad Mohammad Posted August 30, 2011 Share Posted August 30, 2011 .2. [] = absolute value A B [a+b+c] [a]++[c] column B is greater. Because [a]++[c] always makes a positive number Quote Link to comment Share on other sites More sharing options...
bitsgrasim Posted September 13, 2011 Share Posted September 13, 2011 2. Ans D.(can not be determined) Ex. trail-1 : a =1 b=2 c=3 (A=B) trail:2 : a=-1 b=-2 c=-3(A=B) Trail:3 a=1 b=2 c=-3 (A 3. 4-(1/x)= 4x 4x-1 =4x^2 => 4x^2-4x+1=0 => (2x-1)^2=0 (2x-1)=0 x=1/2 Quote Link to comment Share on other sites More sharing options...
annabel398 Posted September 14, 2011 Share Posted September 14, 2011 (edited) Question 1: 4 mats of radius 1 would cover 4 x (pi x 1squared) = 4pi 1 mat of radius 2 would cover 1 x (pi x 2squared) = 4pi Try it with r=3 4 x (pi x 3squared) = 36pi 1 x (pi x 6squared) = 36pi Try it with r=1/2 4 x (pi x 1/2squared) = 1pi 1 x (pi x 1squared) = 1pi The key here is that you're always taking 4 x (the square of the radius) and comparing it to (2 x radius)squared. Factor (2 x radius)squared = 2squared x radius squared, and since 4 = 2squared, they're going to be the same always. Edited September 15, 2011 by annabel398 Quote Link to comment Share on other sites More sharing options...
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