Sponsored Ad:
Results 1 to 6 of 6

Thread: few sample problems

  1. #1
    Trying to make mom and pop proud
    Join Date
    Aug 2011
    Posts
    14
    Rep Power
    9


    Good post? Yes | No

    few sample problems

    Sponsored Ad:
    1.
    A B

    Max surface area covered by 4 Max surface area covered by 1 place mat with
    circular place mats with radius R radius 2r.

    2. [] = absolute value

    A B

    [a+b+c] [a]+[b]+[c]



    3.

    4-1/x = 4x

    I thought I did this one right but for some reason my answer is not coming out right.

    Thanks for the help everyone!!!!!!!

  2. #2
    Trying to make mom and pop proud
    Join Date
    Aug 2011
    Posts
    14
    Rep Power
    9


    Good post? Yes | No
    i apologize for question 1. It is supposed to be separated. 4 place mats radius r and 1 place mat radius 2r. Sorry

  3. #3
    Within my grasp!
    Join Date
    Nov 2010
    Location
    egypt
    Posts
    118
    Rep Power
    10


    Good post? Yes | No
    hey , am just beginner in math , but i have an idea about third question

    what was your answer , 3/4 , or what , here is how this come with me

    4-1 4x
    ___ = ___

    x 1

    then we can use multiplying method and yield 4x = 4-1 then 3/4

    maybe am wrong , you have to search more

  4. #4
    An Urch Guru Pundit Swami Sage Riyad Mohammad's Avatar
    Join Date
    Feb 2009
    Location
    Bangladesh
    Posts
    901
    Rep Power
    15


    Good post? Yes | No
    .2. [] = absolute value

    A B

    [a+b+c] [a]+[b]+[c]

    column B is greater. Because [a]+[b]+[c] always makes a positive number

  5. #5
    Trying to make mom and pop proud
    Join Date
    Sep 2011
    Posts
    7
    Rep Power
    9


    Good post? Yes | No
    2. Ans D.(can not be determined)

    Ex.
    trail-1 : a =1 b=2 c=3 (A=B)
    trail:2 : a=-1 b=-2 c=-3(A=B)
    Trail:3 a=1 b=2 c=-3 (A<B)

    3.
    4-(1/x)= 4x
    4x-1 =4x^2
    => 4x^2-4x+1=0
    => (2x-1)^2=0
    (2x-1)=0
    x=1/2

  6. #6
    Eager!
    Join Date
    Sep 2011
    Location
    USA
    Posts
    71
    Rep Power
    9


    Good post? Yes | No
    Question 1:

    4 mats of radius 1 would cover 4 x (pi x 1squared) = 4pi

    1 mat of radius 2 would cover 1 x (pi x 2squared) = 4pi

    Try it with r=3
    4 x (pi x 3squared) = 36pi
    1 x (pi x 6squared) = 36pi

    Try it with r=1/2
    4 x (pi x 1/2squared) = 1pi
    1 x (pi x 1squared) = 1pi

    The key here is that you're always taking 4 x (the square of the radius) and comparing it to (2 x radius)squared.
    Factor (2 x radius)squared = 2squared x radius squared, and since 4 = 2squared, they're going to be the same always.
    Last edited by annabel398; 09-15-2011 at 01:00 PM.

Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Similar Threads

  1. Replies: 5
    Last Post: 02-27-2010, 07:06 PM
  2. Concepts of Inequality - Need Clarity on Sample Problems
    By vineejay in forum GMAT Problem Solving
    Replies: 21
    Last Post: 11-17-2008, 01:04 PM
  3. math formulas and sample problems
    By jazz in forum GMAT Problem Solving
    Replies: 1
    Last Post: 01-02-2006, 08:07 PM
  4. Sample Qs?
    By mazyar in forum GRE Biochemistry, Cell and Molecular Biology
    Replies: 2
    Last Post: 09-17-2004, 02:38 PM
  5. One Sample
    By Yazynin in forum GMAT Sentence Correction
    Replies: 3
    Last Post: 10-21-2002, 04:03 AM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •