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Thread: Stumped by Percentile solution

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    Stumped by Percentile solution

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    This is a Manhattan question. I have a problem with the solution. Kindly help.

    300 test results are integers ranging from 15 to 75, inclusive. Dominick's result is clearly in the 80th percentile of those results, not the 79th or the 81st.

    Quantity A: Number of other test results in the same percentile as Dominick's
    Quantity B: Maximum number of other test takers with the same result as Dominick's


    OK in summary, the solution says that regarding value of Quantity B,
    only two more people at most could have same score as Dominick as another person with the same score would have to be in the 81st percentile.

    From what I know, percentiles will be calculated using the last score from the 80th percentile group and the first value from the 81st percentile group. So, say all three scores in the 80th percentile were 58, and only the first (or even first two) scores in the 81st group were 58, the 80th percentile would be calculated by taking average of last value of 80th and first value of 81st and in this case it would bring 58 at the 80th percentile. This means that more than 2 students would have the same score as Dominick..

    Can someone clarify the aforementioned problem?
    Attached Thumbnails Attached Thumbnails Stumped by Percentile solution-untitled.png  

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