Sponsored Ad:
See the top rated post in this thread. Click here

# Thread: Formulae and Shortcuts - making life easier!

1. ## Formulae and Shortcuts - making life easier!

Sponsored Ad:
Mixtures first....

1. when you mix different quantities (say n1 and n2) of A and B, with different strengths or values v1 and v2 then their mean value vm after mixing will be:
Vm = (v1.n1 + v2.n2) / (n1 + n2)

you can use this to find the final price of say two types of rice being mixed or final strength of acids of different concentration being mixed etc....

the ratio in which they have to be mixed in order to get a mean value of vm can be given as:
n1/n2 = (v2 - vm)/(vm - v1)

When three different ingredients are mixed then the ratio in which they have to be mixed in order to get a final strength of vm is:
n1 : n2 : n3 = (v2 - vm)(v3 - vm) : (vm - v1)(v3 - vm) : (v2 - vm)(vm - v1)

2. If from a vessel containing M units of mixtures of A & B, x units of the mixture is taken out & replaced by an equal amount of B only .And If this process of taking out & replacement by B is repeated n times , then after n operations,

Amount of A left/ Amount of A originally present = (1-x/M)^n

3. If the vessel contains M units of A only and from this x units of A is taken out and replaced by x units of B. if this process is repeated n times, then:

Amount of A left = M [(1 - x/M)^n]

Ths formula can be applied to problem involving dilution of milk with water, etc...

(All these formulae have been taken from a test prep book issued by a private coaching center)   Reply With Quote

2. thanxxxxxxxxx    Reply With Quote

3. Lets make this thread an archive of formulae. (I dont know if there already exists one in the forum. I havent gone through all previous mails)

Everybody make an attempt to post any formula or short cut that you have got. Be it a standard formula that everybody knows or a rare one. coz there are people in this forum who are from non-math background and they might find it useful. (even if you are not sure how a formula works, as long as you know the formula does work for all cases, post it). So, lets get the ball rolling...

P.S. for any clarifications regarding how a formula works, start a new thread and let this thread be exclusively for listing formulae. that way we can reduce the length of this subforum and enable those, who will probably read this as a last minute revision, to spend lesser time...  Reply With Quote

4. Thanks Suja.   Reply With Quote

5. I agree with you , we should have separate thread on formuls for the last minute glance before the real gre.  Reply With Quote

6. Thanks a lot Suja. I hope this thread goes ROCKING jus like the PROBABILITY thread which I started b4.   Reply With Quote

7. More formulae:

PROGRESSION:

Sum of first n natural numbers: 1 +2 +3 + .... + n = [n(n+1)]/2
Sum of first n odd numbers: 1 + 3 + 5 + .... upto n terms = n^2
Sum of first n even numbers: 2 + 4 + 6 + ... upto n terms = n(n+1)

ARITHMETIC PROGRESSION

nth term of an Arithmetic progression = a + (n-1)d
Sum of n terms in an AP = s = n/2 [2a + (n-1)d]
where, a is the first term and d is the common differnce.

If a, b and c are any three consequtive terms in an AP, then 2b = a + c

GEOMETRIC PROGRESSION

nth term of a GP is = a[r^(n-1)]
sum of n terms of a GP:
s = a [(r^n - 1)/(r-1)] if r > 1
s = a [(1 - r^n)/(r-1)] if r < 1]

sum of an infinite number of terms of a GP is
s(approx.) = a/ (1-r) if r <1

If a, b and c are any three consequtive terms in a GP, then b^2 = a + c

PS: Everybody!!! please contribute or this thread will never grow.  Reply With Quote

8. suja great job   Reply With Quote

9. Problems on trains

a km/hr = (a* (5/18)) m/s

a m/s = (a* (18/5)) km/hr

Time taken by a train of length l metres to pass a pole or a standing man or a signal post is equal to the time taken by the train to cover l metres.

Time taken by a train of length l metres to pass a stationary object of length b metres is the time taken by the train to cover (l+b) metres.

Suppose 2 trains or 2 bodies are moving in the same direction at u m/s and v m/s, where u>v, then their relative speed = (u-v) m/s

Suppose 2 trains or 2 bodies are moving in the opposite direction at u m/s and v m/s, where u>v, then their relative speed = (u+v) m/s

If 2 trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s, then the time taken by the trains to cross each other = (a+b)/(u+v) sec

If 2 trains of length a metres and b metres are moving in same directions at u m/s and v m/s, then the time taken by the faster train to cross the slower train = (a+b)/(u-v) sec

If 2 trains(or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then

(A's speed) B's speed) = (root(B):root(A))  Reply With Quote

10. Good job manwithmissions!!!

TM...wake up. post more formulae...  Reply With Quote

#### Thread Information

##### Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•