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What is the least number which, when divided by 52, leaves 33 as the remainder, and when divided

by 78 leaves 59, and when divided by 117 leaves 98 as the respective remainder ?

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Guest rak123

Number has to be of the form:

52x + 33 & 117y + 98

or

78x+59 & 117y + 98

 

Following any of the two conditions, a number which satisfies both condition can be found. All we need to do then is to check whether it satisfies the third condition too.

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