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denizen06

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  1. The mode will be 2 and 3
  2. 1) A college has 9 basketball players. A 5-member team and a captain will be selected out of these 9 players. How many different selections can be made? (2) How many odd numbers between 50 and 450 can be written with the elements of the set {0,1,2,3,4,5}? Stickler take a look at no. 1
  3. Thirty hospital students who had been treated for a disease were given a new treatment in a research study. They were asked to evaluate whether five symptoms,H, L, P, T and V were made better or worse by the new treatment compared to the old treatment. for each symptom, each patient used one of the five ratings: 2: much better 1: somewhat better 0: neither better nor worse -1: somewhat worse -2: much worse For each symptom , the added sum and added deviation of the ratings are listed below. Symptom ===== Sum of 30 ratings ===== Standard deviation of 30 ratings H ===== 12 ===== 1.40 L ===== 35 ===== 0.69 P ===== -33 ===== 0.79 T ===== -26 ===== 0.43 V ===== 2 ===== 0.89 Based on the sums of ratings alone,how many of the symptoms must have at least one rating of -2? a. None b. One c. Two d. Three e. Four
  4. This was conversation between two former members. Anyone of you know something about mode ? >>>>>>>>vinod2491984 : if a there are two values which have same frequency then what will be the mode of that number.. for example what is the mode of 2,2,3,3 >>>>>>>>>>>>sri830 : The mode will NOT be the average of those two. But mode will be 2, 3. So in this case you will have two modes.
  5. quant comparison quant comparison [ Q1 ] 8^7 8^6 + 2.8^6 + 4.8^6 Please find the cases when dot (.) stands for multiplication or decimal point dot [ Q2 ] A printer numbered consecutively the pages of a book , beginning with 1 on the first page in numbering the pages, he printed a total of 396 digits.. the number of pages in the book. 167 [ Q3 ] seven one dollar bills are to be distributed among lucia, gomez and zomingo .. so that A. each person receives at least do $1 B. at least one person receives at least $ 3 [ Q4 ] (sq.root of 38) + (sq. root of 45) 12
  6. These are old problems. May be not discussed for many days. Hope this would be a practise session for those who are going to take GRE soon. And for new members like me it is helpful also. [1] A guy throws a pair of dice. If the sum of the numbers on the dice is even, then the person tosses a coin. What is the probability of him getting a head? [2] A guy throws a pair of dice. If he doesn't get the sum as even number, he throws the dice again and again untill he gets it. And then he tosses the coin. What is the probability of him getting a head? [3] jewels in certain tiarea constists of diamonds, rubies, and emeralds...the ratio of diamonds to rubies is 5/6 and ratio of drubies to emeralds is 8/3. what is least no. of jewels that could be in tiara. 16 22 40 53 67 [4] how many positive integers less than 20 are equal to the sum of a positive multiple of 3 and a positive multiple of 4? a. 2 b. 5 c. 7 d. 10 e. 19
  7. Dont want to see such problems in real GRE. Do you agree mates?
  8. denizen06

    Sd

    I got you dude long time ago. For this kind of problem you are great. Anyway what is your subject field? What are you doing?
  9. I wasn't . That is still enigmatic to me. Can you elaborate this one for me. I would be glad.
  10. No dude, We are getting the wrong turn. I beleive so. t_g's second answer is right. It says that there will always be SSSS but nowhere IIII Yes there may be III or II Think about it .
  11. Be easy s_n. That was a tough explanation. I can't catch those. And wydiwyg you can do it without combination directly If all the 4 cards are heart then prob = ( 13 * 12 * 11 * 10 ) / ( 52 * 51 * 50 * 49 ) now cards are of same suit. So it can be hearts, claps, diamond, spades Hence answer = 4 * ( 13 * 12 * 11 * 10 ) / ( 52 * 51 * 50 * 49 )
  12. Thanks priyanka for the nice problem and thanks Daniel Sadoc for the sollution. Problem was very interesting.
  13. Yes now you got my sight. But we should check out the correct answer. Who post this problem? Give us the answer, plz? I just want to see my weekneas.
  14. [1] 1 birth in 3 s 1 death in 10 s 10 birth in 30 s 3 death in 30 s 7 increase in 30 s hence 7 / 30 [2] stickler did some mistake priyanka is right it is 45000
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