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Thanks Mits!

I'm having trouble seeing how to set this problem up. I'd appreciate knowing how someone else would work it. The problem: "The graph of the equation y=ax+b, where (ab) doesn't equal 0, has equal x and y intercepts." Column A: the slope of the graph Column B: -1

Okay, yes, your responses make sense. I wasn't taking the order of the rolls into account. Thanks!!

Thanks for your response, Muaztrek! I understand your method and how it solves the problem. I suppose my rationale for answering the way I did had to do with what I read in the probability section of ETS's "Math Review for the GRE" manual (I'm not a math person, as you can tell). In there, it says, "If events E and F are independent events, then P(E and F)=P(E)*P(F)." My question is: why doesn't this method apply to the problem above?

I'm having trouble understanding why my method is wrong here. The question: Throw: ----- Outcome: -- 1 ---------- Lose $3.00 -- 2 ---------- Lose $2.00 -- 3 ---------- Lose $1.00 -- 4 ---------- No Effect -- 5 ---------- Win $1.00 -- 6 ---------- Win $5.00 The results of throwing a single die in a certain gambling game are shown in the table above. What is the probability that a player will have won at least $5.00 after two throws? A) 1/36, B) 1/12, C) 1/9, D) 5/36, E) 1/6 My method was: You must roll a 6 (1 in 6 chance) in at least one of the rolls, and you must roll either a 4, 5 or 6 in the other roll (3 in 6 chance), so the probability would be (1/6)*(3/6), which is equal to 1/12. Would someone mind to point out how my logic is flawed, please? Thanks!

Your difficulty may result from assuming that the 5 integers must be consecutive integers. (I know because I did that on this question and got it wrong!) The number could be 12345 or it could just as easily be 92316. My method of solving would just be to try a few numbers, and they all end up being disivible by 9. Does this help? --- edit: sorry, posted right at the same time as coolgeek--obviously his method is much better! ;)