e.cartman

It's actually a simple problem if you are not distracted by the right-angle like I was. Just 1 step: Exterior angle = sum of interior opposite angles. PRS = PQR + QPR Stmt 1: PRS = PQR + 30 => PRS - PQR = 30. suff Stmt 2: We again get QPR=30 and same result. suff No need for PSR to be right angle. HTH

3/4 - 2/5 = ans. Smallbee, imo your final fraction should be 35/100

Question translates to jfk = 1/2 miami; miami = 4 logan. It is not even ambiguous. I think OA is telling people what to think! :)

Imo E.

means not-equal-to. Imo E.

Imo D. Either way it looks like median will be equidistant from smallest and biggest. OA please.

Thanks for pointing that out silvanahv. I see it is essentially same as Bertrand's box; when the problem says drawn-out counter is white, it is analogous to eliminating the box with 2 silver coins, so it is really just reworded version of the same.

Question: When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, remainder is 3. What is the remainder when product nt is divided by 15? 1) n-2 is divisible by 5 2) t is divisible by 3

I took long time for this so I hope there is a short-cut. Together, Stmt 1: n=3i+2=5j+2 By trial and error, remainder of n by 15 would be 2. Donno about t, so insuff. Stmt 2: t=5p+3=3q by trying small values for p, remainder of t by 15 is 3. Donno about n so insuff. Together, n=15a+2 t=15b+3 So multiplying, remainder of nt by 15 has to be 6.

That's why this is a good problem. Probability is not 1/2. You need to consider drawing w1 separate from w2 because they are equally likely different events. So probability is 2/3 as pointed out before.

Multiply Nr and Dr by 2^4 2^4/10^something =16/10^something => 2 non-zero digits.

good question, monty-hallish.

Imo D. Let angle subtended at center be x. 4pi/3 = 2pi*4 * x/360 => x =60 If center is O, ORU is an equilateral triangle so RU=4.

same method as thankont. This is weighted average where the weight on 20 is more than weight on 10 since y>x. So result will be greater than (10+20)/2 but less than 20.

Question says factors, not prime factors.