Abhishek009

Although Professor Crone’s arguments are creative, they fail to convince her readers that her representation of Meccan trade should be taken as fact. ​Hence would choose A

The following lines tells us the entire picture .

Going through the given options A , B and E can be ruled out based on the following logic - A : As much as , refers to quantitative comparison , whereas we are interested in the Number . B : Twice as many as 1977 is incorrect as it gives the impression 2 times 1977. C : Double what it , " It " is ambiguous , it might refer to clerks or female ministers and its not clearly specified. E : Modifies the number of Clergies , whereas it must modify the Female ministers.... Hence C is correct..

The best way for solving such questions is by using Options given as answer choices... So , if Possible kindly give some options.

5 pencils + 3 pens = 30 cents--------------->(1) 4 pencils + 4 pens = 32 cents---------------->(2) (1) * 4 => 20 pencils + 12 pens = 120 cents------------>(3) (2) * 5 => 20 pencils + 20 pens = 160 cents------------>(4) Now subtract ( 3 ) from ( 4 ) .... 8 pens = 40cents so 1 pen = 5 cents... Now substitute the value of 1 pen in equation number 1 : 5 pencils + 3 pens = 30 cents Or , 5 pencils + 3 * 5 = 30 cents Or, 5 pencils + 15 cents = 30 cents So 5 pencils = 15 cents Hence Cost of 1 pencil is 3 cents....

Great question , go thru this - Math Forum: Ask Dr. Math FAQ: 0! = 1

Let total dozen of eggs sold in may be 3 Then total dozen of eggs sold in April is 2 Eggs sold in June => 2 times that of April = 4 Now find the total price of eggs month wise : April => 2 * $1.26 = 2.52 May => 3 * $1.20 = 3.60 June = 4 * $1.08 = 4.32 Total Price of Eggs over the three months is 10.44 So average Price per dozen is Total Price / Total No of Dozens sold => 10.44 / 9 = 1.16 Hence answer is 1.16......

Left hand side : (x-1)!/(X-3)! *2= (x-1)(x-2)(x-3)!/(X-3)!*2 Now (x-1)(x-2)(x-3)!/(X-3)! = > (x-1)(x-2)*2 Hence : (x-1)(x-2)*2 = 72 So , (x-1)(x-2) = 36 Now proceed....

p is the product of the integers from 1 to 30 means p = 1 * 2 * 3* ..............28* 29 * 30 p = 30! Now we gotta find the no of 3's in 30! 30/3 = 10 10 /3 = 3 3 /1 = 1 Finally we add them up to get the total no of 3's in 30! is 14 ( 10 + 3 + 1 )...

CASE I n = 17x + 5 Again CASE II n = 23y + 14 Now in both Cases n is common so : n => 17x + 5 = 23y + 14 or , 17x-23y = 9 Thus answer is B...:rolleyes:

both x and y is the correct usage and it works fine here , without distorting the meaning of the sentence.....

Plugin in some values of m to check the value of x and proceed..... case 1 take m = 1 Then 1/2^m + 1/2^m = 1/2^x 1/2^1 + 1/2^1 = 1/2^0 So m = 1 & x = 0 ( m - 1 ) Case 2 Take m = 2 1/2^m + 1/2^m = 1/2^x 1/2^2 + 1/2^2 = 1/2^1 Here again x = m -1 So from here you can calculate the value of x......

Same here will go with Whom...

IMO D Correct usage is - Prevent someone from doing something

Defintely the answer is C due to the continuity , Not only ______________ but also_______________