rina777
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Everything posted by rina777
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A.P(both will decode the message)=0.70 * 0.80 = 0.56 B.P(at least one of them will decode the message)= 1- P(none of them will decode the message)= 1-(1-.70)(1-.80)=0.94 C.P(neither of them will decode the message)=(1-.70)(1-.80)=.06
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Here we have to use combination formula because here order is not considerable.
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2. the answer is c
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Let the asking price is x, after reducing the asking price 10% it becomes .9x. here, .9x=1953 so x=2170, which would make 40% profit. so cost price is (100*2170)/140=1550 , which makes (1953-1550)=$403 profit
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@ premprakash, for #2 didn't you miss the negative integer -1 to -12 and 0 is also an integer. so the total is 25.
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For Question#1 I got 3 too.
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Hi tractable, I don't know what to say. I think if you could manage a good night sleep before test night, surely you could manage your expected score. wish you all the best.
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Is 0 is a positive integer? I think it is neutral ie neither positive nor negative.....
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wish you very good luck tractable!!!!!!:tup:
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(2^30-2^29)/2 = 2^28(4-2)/2 = 2^28 so A=B and the answer is C
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3. the answer is D 31%.
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2.the answer is 3/4
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1.100y
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2. Least Common factor of 225 and 216 is 2^3*3^3*5^2 so the least possible value of a+b+c would be 3+3+2=8
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To find the mean we have to multiply all the score with respective frequency and add them. 1*1+3*2+4*2+5*7+6*8+7*10+8*11+9*5+10*4=1+6+8+35+48+70+88+45+40=341 then we have to divide it with total no of student 50. so we get mean is 6.82
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As the total is even, we have to take average of number at n/2 and (n/2)+1
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there are total 50 student. the median is the mean score of 25th and 26th student. they both got 7. so the median is 7.
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the equiangular ocatagon is a square with cutoff corners. if divide it we get 5 full square(each with 1 unit) with total area 5unit and 4 half square with total area 2. so the area of the whole octagon is 5+2=7 square unit
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1142241/(121=11*11) 1142241/11=12931 12931/11=1175.5454545........... so the fifth digit is 5