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Brent Hanneson

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Brent Hanneson last won the day on June 13 2011

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  1. 1,6k4 is a 4-digit number. So, 1^4 + 6^4 + k^4 + 4^4 = 16k4 Evaluate: 1 + 1296 + k^4 + 256 = 16k4 Simplify: 1553 + k^4 = 16k4 Whatever k is, it must be the case that the UNITS digit of k^4 is 1, so that 1553 + k^4 = 16k4 Test some values.. k = 1: 1^4 = 1, so we get: 1553 + 1 = 1614 NO GOOD k = 3: 3^4 = 81, so we get: 1553 + 81 = 1634 WORKS!! Answer: k = 3 Cheers, Brent
  2. A quick solution is to say that the original 20 measurements were all 34 That is {34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34} These values definitely have an average of 34 For security reasons the scientist coded the data by multiplying each of the measurements by 10 and then adding 40 to each product. 34 times 10 equals 340. Add 40 to get 380 So, the 20 coded values are {380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380} New average = 380 Answer: B Cheers, Brent
  3. There's no math required for this question. The strip can be any value, since we could choose a certain width for the strip and then just shrink or expand the inlay until the ratio of (inlay area): (strip area) is 25:39. Cheers, Brent
  4. Another way to state this question is: What is the greatest common factor of 4000 and 180?
  5. G = 10^100 We can rewrite this as follows: G = (10^3)(10^97) Or we can say G = (1000)(10^97) So, G/8 = (1000)(10^97)/8 = (125)(10^97) G/5 = (1000)(10^97)/5 = (200)(10^97) G/4 = (1000)(10^97)/4 = (250)(10^97) G/2 = (1000)(10^97)/2 = (500)(10^97) So, G/8 + G/5 + G/4 + G/2 = (125)(10^97) + (200)(10^97) + (250)(10^97) + (500)(10^97) = (10^97)(125 + 200 + 250 + 500) = (10^97)(1075) This evaluates to be 1075 followed by 97 zeros So, the sum of the digits = 1 + 0 + 7 + 5 + a bunch of zeros = 13 Answer:
  6. We have an online study guide here - Study Guide - Overview | Greenlight Test Prep Online Course It can be used in conjunction with our free GRE video course. Cheers, Brent
  7. You will notice that I never said that 12 people can be seated at a round table in 11! ways (Chromepal made this claim). I'm not a big fan of "people sitting at a circle" questions, because the assumption is that the seats are identical. Since this is not stated in the question, I solved it in a way that does not require us to make this assumption. Cheers, Brent
  8. When it comes to remainders, we have a nice rule that says: If N divided by D, leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc. For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc. When the positive integer n is divided by 3, the remainder is 2 So, some possible values of n are: 2, 5, 8, 11, 14, 17, 20, 23, 26, 29,....etc When n is divided by 5, the remainder is 1. So, some possible values of n are: 1, 6, 11, 16, 21, 26, 31 .... etc We can see that 11 is the smallest number that BOTH lists share For more info on remainders, see our free video: GRE Integer Properties | Greenlight Test Prep Cheers, Brent
  9. 175 flashcards covering every formula, concept and strategy needed for the quantitative sections of the GRE. Each flashcard is linked to a corresponding video lesson from Greenlight Test Prep’s free GRE course. The slideshow is accessed via our SlideShare page ( ) where you can download it to your smartphone/computer for offline viewing. Cheers, Brent – Greenlight Test Prep
  10. If you're still looking for GRE resources, we have a free course with 500+ videos, 600+ practice questions and 5 full-length practice tests. Cheers, Brent - Greenlight Test Prep
  11. Brent Hanneson

    Problem

    You're absolutely correct - nice catch! I have reposted my answer above. Cheers, Brent
  12. Brent Hanneson

    Problem

    Let's examine the two EXTREME values of a. Case a: The GREATEST value of a If the values are strictly increasing (i.e., no values are equal), them a could be a little bit smaller than 8.5. So, a could equal 8.499999999999 For all intents and purposes, let's just say that the a COULD equal 8.5 In this case, 2a = (2)(8.5) = 17, which means the range = 17 - 3.7 = 13.3 Case b: The SMALLEST value of a If the values are strictly increasing (i.e., no values are equal), them 2a could be a little bit bigger than 9.2 So, 2a could equal 9.20000000001 For all intents and purposes, let's just say that the 2a COULD equal 9.2 This mean a = 4.7 This is fine, because we're told that a is greater than 4.1. If 2a = 9.2, then the range = 9.2 - 3.7 = 5.5 Now that we've examined the EXTREME cases, we can see that the range can be between 5.5 and 13.3 Answer(s): C, D and E Cheers, Brent
  13. Please post only one question per thread. Otherwise things can become pretty complicated when there are discussions on multiple questions. Cheers, Brent
  14. Way out of scope for the GRE. Cheers, Brent - Greenlight Test Prep
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