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abhistud0554

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  1. Hi Amanda,Suppose we break the final solution down as the addition of 3 separate parts. I understand that we have to multiply 1*5 cents and 1*10 cents which correspond to the 2nd and 3rd parts. But I don't understand how we can multiply 4*1 to get a value of 4 cents for the 1st part. The question states that 4 pennies is equal to 1 cent. So the value of cents from the 1st part should be 1 cent only right? Please help me understand.
  2. Hi, I'm having trouble understanding this quantitative comparison word problem from Manhattan GRE book. Its on page 125 the 7th problem. The problem states: Jared has four pennies(one cent), one nickel(five cents) and one dime(ten cents). Column A - The number of different cent values that Jared can achieve using one or more of his coins. Column B - 20. Which is greater Column A or Column B ? Answer - Column B. The explanation given in the book is Jared can achieve anywhere from 1 cent to 19 cents. But I thought he can have a maximum of 16 cents only i.e. if you add up the value of the total cents coins he has? I don't understand how he can have 19 cents. Could someone plz help me understand this and the procedure to get Column A's value? Thanks.
  3. Thank u so much gbd97..Ur explanation really helped make thing clear..
  4. Hi, I was working on this problem from Manhattan GRE Word problem book. The 2nd problem in Page 121. And I can't seem to understand a certain portion of the problem. A Salad dressing requires oil, vinegar and water in the ratio of 2:1:3. If Oliver has 1 cup of oil, 1/3 cup of vinegar and 2 cups of water, what is the maximum number of cups of dressing that he can mix? Solution from the book : 2 cups. Explanation from the book : Try the limits. If Oliver used 1 cup of oil, his recipe would require 1/2 cup of vinegar and 1 1/2 cups of water. He does not have enough vinegar. If he used 1/3 cup of vinegar, he would need 2/3 cups of oil and 1 cup of water, both of which he has. He would then have 2/3 + 1/3 + 1 = 2 cups of dressing. He cannot possible make more dressing than this because he does not have any more vinegar. I don't understand how they calculate the ratios. Meaning if Oliver decided to use 1 cup of oil, how do we determine that he needs 1/2 cup of vinegar and 1 1/2 cups of water and so forth. I know we have to use the given ratio 2:1:3 to arrive at this but I'm not able to correlate to get the solution. Please help me understand. Thanks.
  5. Hey gr8acky, Tats so gr8!! Very helpful. Thanks! I'm glad I wasn't missing something. Could you please point me to the link where you found this errata sheet, in case I missed some other problem because of the errors? Thank you!
  6. Hi there, I was having the exact same doubt a few weeks back when I was working on this question. Specifically how they got 76 in the equation x2 + 2x +76 = 100 ? Shouldn't it be 77? Did you figure it out?
  7. Hi, I was going through a very simple GRE Ratio problem. But I'm not able to understand one tiny concept in it. It is currently raining cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are raining? Answer - If the ratio of cats to dogs is 5: 6 then there are 5x cats and 6x dogs (using the Unknown Multiplier). Express the fact that there are 18 fewer cats than dogs with an equation: 5x + 18 = 6x x = 18 Therefore there are 6(18) = 108 dogs. I don't understand the equation above. The questions says 18 "fewer" cats than dogs so isn't the equation supposed to be 5x - 18 = 6x ?
  8. Yes that helps. Thanks. Although could you please tell me how you got the values for x as x = 1 + sqrt(2) and x = 1 - sqrt(2) for the quadratic equation x^2 -2x - 1 = 0. Are they indeterminate values?
  9. Hi, I'm having trouble understanding this problem. Specifically why Choice C is incorrect. If a > 0 and b Indicate all such statements. A. They have opposite signs. B. Their sum is greater than zero. C. Their product equals -b. Solution: A and B. I can understand why A and B are correct. A is correct because constant term at the end of a quadratic equation is positive when two solutions are of the same sign. However in given equation constant is b which is less than zero. Thus 2 solutions must be of opposite signs, so choice A is correct. As for Choice B the coefficient of x term in a quadratic ens is the negative of the sum of the 2 solutions. In given equation, coefficient is -a , which is negative. Thus Choice B is correct: The sum of 2 solutions must be greater than zero. However I can't understand why Choice C is incorrect. I thought this choice is also right since the constant of a quadratic equation is the product of the 2 solutions. In this case we have Positive a and Negative b, the product of which gives us -b. So Choice C is correct am I right? Or am I missing something? Please help me understand.
  10. Hi, I'm having trouble understanding how to solve this inequality problem. If -4 A) -3 B) 0 C) 4 D) 6 E) 9 Solution E. Step 1: Extreme values for a are GT(-4) and LT(4). Extreme values for b are GT(-2) and LT(-1). where GT - Greater Than; LT - Less than Step 2:Thus from step 1, we can understand that a can be positive or negative while b can only be negative, so ab can be positive and negative. Step 3: The most negative ab can be is GT(-2)*GT(4) = GT(-8) The most positive ab can be is GT(-4)*GT(-2)= LT(8) Can someone please help me understand step 3? I don't understand how they got the most negative and positive values for a and b individually, and how multiplying 2 extreme values together work when they are not both positive like GT(-2)*GT(4) = GT(-8) or if both are negative GT(-4)*GT(-2)= LT(8)?
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