Tristar

Good essay. I would just add the role that scandals play in manipulating the public opinion and how fast this can be delivered to the masses by various mass media outlets. What are the costs of such manipulation? What are the ways to eradicate such practices?

I think you could make a jump from a good essay to a great one by considering the following points: 1) What are these positive and negative actions? Do we have a clearly defined boundary between positive and negative actions? Why or why not? 2) What about the discipline? Can you encourage discipline with only positive actions? Why or why not? 3) Does the age, cultural background, educational level of people matter on deciding when to ignore negative actions and when not? 4) Would the urgency of extraordinary situations (like wars, riots, etc) lead to increased reliance on using negative actions?

Here are some tips for your improvement: 1) Try to make a simple analysis of the given situation. For instance, you could ask yourself the following questions: What does it look like when corporations try to maximize their profits? Can we measure all actions that lead to profit maximization by corporations? What is the welfare of the nation at large? Can we measure such welfare? How? 2) The next step is to determine the ways in which such maximization of profits by corporations affect the welfare of the society. It could have a positive, a negative or a neutral effect in theory. But, what does the real situation look like. Provide examples. 3) Take a stance (whether you agree or disagree with the statement) and provide clear arguments which back your position. 4) Provide the meaningful conclusion to all your paragraphs mentioned previously. Hope this helps.

Hi there! I would rate your Essay on 3 Principles: Grammar, Argumentation, and Integrity. The grades of the sub-parts is as follows: Grammar (5/10), Argumentation (3/10) and Integrity (2/10). For the sake of brevity I will not dwell on the grammatical mistakes here. In your arguments, it is important to show why do you think that costs and efforts to save endangered species outweigh the benefits (real and potential). It would have been much better if you could show which benefits society derives from keeping endangered species. Also, please note that the direct harmful effect of humans (and not that of the evolution) caused the number of certain species to decrease drastically in the past. It is not clear what do you mean by "deteriorating economy's growth' when you try (unsuccessfully) to link it to the food industry. Your conclusion fails to conclude meaningfully the line of arguments that you propose. So, all in all, you have a great room for improvement! Hope this helps.

The right answer should NOT contain 1, as both "x and y are greater than 1". This is given as a pre-condition in this particular question. Hope this helps. Tristar

Yes, the correct answer is 720 people.

Ans to q2: Total Number of Cases=(2,6); (6,2); (3,5); (5,3) and (4,4) i.e. 5. Now, number five is present in two of these cases (Favorable Number of Cases). Thus, the required probability=2/5. Hence, D.

Ans to q1: 4 adresses can be arranged in 4! ways i.e. 4!=4*3*2*1=24 ways (Total Number of Cases). One letter could be put into its correct envelope in 4 ways (the first letter goes into its correct envelope the rest go into different addresses, the second letter goes into its correct envelope and the rest go into different addresses, etc.). Now, assuming that the letter goes into its correct address, the remaining three letters can be arranged in 3P1ways=3 ways, but in only 2 of those 3 ways do we manage to put remaining 3 letters inside envelopes with different addresses. Thus, we have: 4*2=8 ways (Favorable Number of Cases). The required probability=8/24=1/3. Hence, D.

Answer: 4 people can be selected out of 8 people in 8C4 ways = 70 (total number of cases). Assuming that Andrew is among the 4 volunteers selected, we have 3 remaining spots for 6 candidates (as Karen can't be on the same team as Andrew we do not consider her as a candidate for the first team). Now, 3 people can be selected out of 6 candidates in 6C3 ways = 20 (favorable number of cases). Our required probability P = Favorable Number of Cases / Total Number of Cases = 20/70 = 2/7.

Hi there! Here below is a maths test question for 15-year olds. Just give it a try: A revolving door has three areas within a circular-shaped space. In one minute the door goes around 4 times. Two people can fit in each of the three door sectors. What is the maximum number of people that can enter the building through the door in 30 minutes? (The diameter of the circle = 200 cm, the Exit being located just opposite the Entrance).

Q1.There are 9 candidates being interviewed for a position. Interviews can only be conducted on the days Monday to Wednesday, two interviews per day. The first interview being conducted each day will have two candidates being interviewed together. How many different schedules are possible for a given period? Ans: We have three interviews in all: one on Monday, one on Tuesday and one on Wednesday. We are just considering the first interview to be held on each of these three days. For Monday, there will be 9C2 = 36 different schedules involving BOTH candidates. For, Tuesday, there will be 7C2 = 21 such schedules and for Wednesday 5C2 = 10 different schedules. All in all, there will be 36*21*10= 7,560 different schedules.

I will try to explain this concept in an easy way. When you are given more than one spot where you need to select objects from a wider population (in our case the population of marbles), first find out the required probability for the first spot. In our example, for the first marble to be drawn, the probability that it is going to be red is 6 (favorable number of cases) / 12 (total number of cases) = 1/2. The next step, is to observe that for the second marble the probability of being selected (without replacement) will be different from the probability found in step 1. This is so, because we have one less marble to choose from the remaining population, meaning that the chances of choosing the second marble in the red color is LESS than, say, choosing the second marble in the blue color (5 red marbles left vis-a-vis 6 blue marbles). So, the probability of choosing the second marble in the red color is 5 (remaining red marbles) / 11 (remaining total number of all marbles). So, our required probability is: (1/2)*(5/11) = 5/22. Hope the confusion related to this question is resolved for good.

Here's what I think on this problem: Since the net change out of 100 actions (weeks) is 40 people in the room, the given probabilities need to be adjusted by a factor of (100/104) = 0.961538 (approx.) So, we have: 0.6 * 0.961538 = 0.5769 (approx.). This is closer to answer B, which is 0.55.

In how many different ways can 12 people be seated at two tables with one seating 7 and the other seating 5? Ans: The first sit can be taken by anyone of 12 people, the next sit by the remaining 11 people and so on. The total number of such arrangements is: 12! In my humble opinion, it’s immaterial how we subdivide these arrangements into separate groups be that (5 people at the first table and 7 at the second) or otherwise, or say (6 people at the first table and 6 at the second) still the total number of such arrangements will not change.

There are 5 balls of different colours and 5 boxes of colours the same as those of the balls. Number of ways in which the balls, one in each box can be placed such that a ball does not go to a box of its own colour is? Ans: I solved this problem by the way of making generalizations. If there are just three elements (balls) 1, 2, 3 and three corresponding boxes B1, B2 and B3, then the total number of ways in which each ball can be placed into any one of the boxes B1, B2 or B3 will be given by: 3! = 6 arrangements. These arrangements are as follows: (123), (132), (213), (231), (312) and (321). Out of these 6 arrangements the first two are eliminated outright (as the first ball cannot go into the first position=B1). Out of the remaining 4 outcomes half satisfy the condition and the other half doesn’t. So, the number of ways for arranging 3 balls into 3 boxes such that a ball does not go into a box of its own color will be 2. If we do it for 5 balls and five boxes, then the solution is 48 arrangements (5! = 120 total arrangements, (120/5) = 24 arrangements of 5 elements and we can subdivide 120 arrangements into five columns of 24 arrangements. Then, 120 – 24 = 96 (we eliminate all arrangements starting with 1 placed on the first position out of five). For the remaining 4 columns of 24 arrangements half satisfy our required condition and the other half does not. So, we have: 12 * 4 = 48 arrangements.