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manish8109

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Everything posted by manish8109

  1. hi, George...

    How r u sir????

  2. Refer to Q3: http://www.www.urch.com/forums/gmat-problem-solving/51123-challenge-gmat-help-manish8109-ctg1983-chix475ntu-arjmen.html
  3. Statement 1: k=4a+3 => 5k = 20a+15 => 5k/6 = 20a/6 + 15/6 it will always give different remainder. Ex: If a=1 then k=7 5k=35 => 35/6 = rem=5 If a=2 then k=11 5k=55 => 55/6 rem= 1 Insufficient Statement 2: k=12a+3 => 5k = 60a+15 => 5k/6 = 10a + 15/6 15/6 will always give remainder 3 -------Sufficient Ans(B)
  4. Kth term = (-1)^(k+1) * 1/2^k Ist term = 1/2 , 2nd term= -1/4 IIIrd term = 1/8 T = 1/2 -1/4 + 1/8 -1/16 + 1/32 - 1/64 + 1/128 -1/256 +1/512 -1/1024 = 1/4 + 1/16 + 1/64 + 1/256 + 1/1024 Ans is (D) b/w 1/4 & 1/2
  5. (x/3)/(y/4) = 5/6 => 4x/3y = 5/6 => x/y = 5*3/6*4 => x/y = 15/24 => x/y= 3*5/3*8 => x/y= 5/8-------(Ans)
  6. Q1. Refer to http://www.www.urch.com/forums/gmat-data-sufficiency/48203-gmatprep.html
  7. Let the no. of employees be x Avg. salary = 2000 = total salary/x Total salary=2000x Avg. salary(150 people) = 4000 Salary for 150worker = 4000*150 = 600000 2000x = 600000 + (x-150)*1250 => 2000x = 600000 + 1250x -187500 => 750x = 412500 => x=550 worker
  8. 1. Please Refer to http://www.www.urch.com/forums/gmat-problem-solving/82963-can-someone-show-how-solve-answer.html 3. X/2 at 10:00 am so, X/2/4 i.e. x/8 at 9:00 am-----Ans(A) 5. Correct question A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games? (A) 7 (B) 6 © 5 (D) 4 (E) 3
  9. Refer to http://www.www.urch.com/forums/gmat-problem-solving/48771-2-gmatprep-questions.html
  10. Let the no. of hardback copies sold be x after issuing the first paperback copy 9x + (x+36)= 441 => 10x+36 =441 => 10x=405 => x=40.5 No. of paperback copies sold = 9*40.5 = 364.5-----Ans©
  11. Sum of temperatures=5x Sum of 3 greatest > Sum of the remaining temp. A) Not possible as 6x>5x B) 4x Could be possible C) 5x/3 => 5x-5x/3 = 10x/3 > 5x/3 ----It means 5x/3 is not the sum of 3 greatest temperature. D) 3x/2 => 5x-3x/2 = 7x/2> 3x/2 -----Same reason as above not possible So Maximum sum possible for sum of 3 greatest of these temperatures could be 4x-----ANS(B)
  12. Let the first solution be 400mL i.e. 300 alcohol & 100 ml water Let the Second solution be 100mL i.e. 40 Alcohol & 60 ml water Combining both 340/500 = 34/50=17/25-----ANS
  13. Congratulations.....................
  14. IIL, 3= sqrt(3) * sqrt(3) so, 3*3/sqrt(3) = 3*sqrt(3) *sqrt(3) /sqrt(3) cancel sqrt(3) from both numerator & denominator = 3*sqrt(3) Regards manish
  15. Zuckerman, I concur with you. I only used it to establish that x-y=1/2 where 1/2 is a positive number it means x > y but when if y 1. So, both x & y has to be positive to satisfy both the conditions. It is always better to keep the fractional nature of ratios intact. Regards Manish
  16. X=43k + r r=? Statement 1: X+10=43k => X=43k-10 => X/43 = 43k/43 -10/43 => X/43 = k -10/43 Remainder will be 43-10 =33-----Sufficient Statement 2: X+43 = 10k => X= 10K-43 => X/43 = 10k/43 - 1 k>=5 Value of r will depend upon the value of k if k=5 then x=7 r=7 k=6 then x=17 r=17 Insufficient Ans(A)
  17. r+s>2t => r>2t-s Statement 1: t>s we can say 2t-s > 2t-t => r>2t-s>2t-t => r>t ---------Sufficient Statement 2: r>s => 2r>r+s>2t => 2r>2t =>r>t------------Sufficient Ans(D)
  18. (n-1)(n+1)=24k+r r=? Statement 1: 2 is not a factor of n => n is odd n-1 is even & n+1 is even If n=3 then r=8 n=5 then r=0 n=7 then r=0 n=9 then r=8 n=11 then r=0 For each multiple of 3 we get r=8 & for every other odd number we get r=0 Insufficient Statement 2: 3 is not a factor of n i.e. If n= 2 then r=2 n=4 then r=15 n=5 then r=0 Insufficient Combining both the statement i.e. n is not a multiple of 2 or 3. n=5 then r=0 n=7 then r=0 n=11 then r=0 n=13 then r=0 r will be zero for every odd number which is not a multiple of 3. Sufficient Ans©
  19. Statement 1: A(2) = 5 = A(1)/2 => A(1)=10 A(3) =A(2)/3 = 5/3 A(4)= 5/3/4=5/12 A(1),A(2),A(3) > 1/2 -----There are 3 terms >1/2 Sufficient Statement 2: A(1) - A(2) =5 => A(1) -A(1)/2 =5 => A(1)/2=5 => A(1) =10 Same as above Sufficient Ans(D)
  20. Statement 1: 2x-2y=1 => x-y=1/2 x = 0.7; y = 0.2 (both positive) x = 0.3; y = -0.2 (both are not positive. Insufficient Statement 2: x>y so, x & y could both be positive or both be negative Insufficient Combining both x>y -----Statement 2 x-y=1/2-----Statement 1 It is only possible when x>y & both are positive Sufficient Ans©
  21. a(n) =a(n-1)+k Statement 1: a(1)=24 We don't know about k so insufficient Statement 2: a(8) =10 ------------Median term If k is +ve then there are 7 terms above 10 as a(9)......a(15) If k is -ve then there are 7 terms above 10 as a(1)......a(7) Sufficient Ans(B)
  22. Statement 1: x=2k+1 x=3k Means x could be 3, 9,15 & so on.... so, when x divided by 6 it will always give remainder=3----Sufficient Statement 2: x=12k+3 so, when x divided by 6 => x/6 = 2k + 3/6 -----> will always give remainder 3 Sufficient Ans(D)
  23. Ans is (B) assume no. of person more than 65 yrs are 100 Let no. of men =0 So, women=100 => 10% are employed----Sufficient Let no. of women =0 let no.of men=100=> 20% are employed -----Sufficient let no. of men=50=> 10 are employed i.e. 105of total population women=50 So, what ever is the case Atleast 10% of the population above 65yrs are employed
  24. Let x=2 & y=3 Statement 1: a+b is even N= (x^a)*(y^b) a=2, b=2 ------ Both even then N^1/2 will always be an integer N= (2^2)*(3^2)= 36 => N^1/2 = +/- 6 -----Integer a=3, b=1----------> both odd then N^1/2 will never be an integer N= 2^3 * 3^1 = 24 => N^1/2 ------Not an Integer Insufficient Statement 2: a=1 & b=2 N= 2^1 * 3^2 = 18 => N^1/2--------Not an Integer a=2 & b=2 N= 2^2 * 3^2 = 36=> N^1/2 -------Integer Combining both Either of a or b one should always be even to make a*b even & gor a+b to be even then b should always be even. i.e. N= x^2 * y^b => N^1/2----------Would always be an integer for even a & b. Ans©
  25. Statement 1: If bill amount is 16 then tip=2 i.e. below 15% If bill amount is 29 then tip=4 i.e. below 15% If Bill amount is 20 then tip=4 i.e. above 15% Insufficient Statement 2: Tip=8 it means bill amount is between 40 & 49 so, 8/49 =16.3% >15 % Sufficient Ans(B)
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